f a Random Sample of 450 adults includes 155 who identify as happy, compute an 80% confidence interval for the true proportion of adults who are happy.

Q: Out of 300 people sampled, 156 had kids. Based on this construct a 90% confidence interval for the…

A: X = 156 N = 300

Q: In a survey of 3001 ​adults, 1486 say they have started paying bills online in the last year.…

A: Assuming that the number of people paying bills online has a binomial distribution with n=3001, and…

Q: In a survey of 2865 ​adults, 1413 say they have started paying bills online in the last year.…

A:

Q: A survey of 540 depressed shoppers found at 32% of them shop on impulse. What is the 99% confidence…

A: Given : Sample Size, n = 540 confidence level,c=0.99 Significance level, α…

Q: When Mendel conducted his famous genetics experiment with peas, one sample of offspring consisted of…

A: Obtain the 95% confidence interval estimate of the percentage of yellow peas. The 95% confidence…

Q: A survey of 200,000 boat owners found that 12% of the pleasure boats were named Serenity.Find the…

A:

Q: A survey of 120 female freshmen showed that 9 did not wish to work after marriage.  Find the 99%…

A:

Q: In a survey of 3254 ​adults, 1433 say they have started paying bills online in the last year.…

A: Given X=1433 n=3254

Q: Out of a sample of 500 high school students, 376 said they would prefer to have computers in every…

A: Let X be the number of students who prefer to have computers in every classroom. X here will be a…

Q: In a survey of 2703 ​adults, 1438 say they have started paying bills online in the last year.…

A: We have given that, Number of favorable cases(X) = 1438,   Sample size(n) = 2703 Sample proportion…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: Suppose a statistics instructor believes that there is no significant difference between the mean…

A: Complete solution and answer is given in the image uploaded below  Thanks!

Q: In a random sample of 170 customers, 90 ordered chicken sandwiches for lunch. Construct a 94%…

A:

Q: confidence interval for the proportion of unemployed adults who have been unemployed for more than…

A: Here given  In a survey of 532 unemployed adults, 225 said that they had been unemployed for more…

Q: An accounting firm has 1200 clients. From a random sample of 120 clients, 110 indicated very high…

A: Given : An accounting firm has 1200 clients So,  Population size (N) = 1200 Sample size (n) = 120…

Q: A survey of 400 students at Red Rock College found that 180 planned to take summer classes. Find a…

A:

Q: The Centers for Disease Control and Prevention reported a survey of randomly selected Americans age…

A: Confidence interval for Proportions : The following is the formula for confidence interval of the…

Q: In a recent survey of 200 households, 172 had central air conditioning.  Find the 85% confidence…

A: Given that In a recent survey of 200 households, 172 had central air conditioning That is…

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: Sample proportion=p^=21380z=critical value for 95% confidence interval=1.96n=sample size=380

Q: In a survey of 1005 adults 526 stated construct a 95% confidence interval

A:

Q: Out of 200 people sampled, 42 had kids. Based on this, construct a 95% confidence interval for the…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: Of 127 randomly selected adults, 31 were found to have high blood pressure. Construct a 95%…

A: Given that, Of 127 randomly selected adults, 31 were found to have high blood pressure.  X = 31 N =…

Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…

A: It is given that the proportion of the students who preferred a quarter system to a trimester…

Q: In a survey of 612 randomly selected female college students, 141 report that they had been sexually…

A: Given Information:n=612x=141c=95%=0.95

Q: A survey found that out of 900 workers, 150 said they were interrupted by frank phone calls. Find…

A:

Q: In a survey of 6000 women, 3431 say they change their nail polish once a week. Construct a 99%…

A: Confidence interval:The (1-α) % confidence interval for proportion p is given by,

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community…

A: Given that, Out Of 380 randomly selected medical students, 21 said that they planned to work in a…

Q: In a sample of 300 people, 154 said that they watched news on television. Find the 90% confidence…

A: According to the given information in this question We need to find the 90% confidence interval of…

Q: In a survey of 3260​ adults, 1456 say they have started paying bills online in the last year.…

A: Givenn=3260x=1456p^=xn=14563260=0.4466

Q: Of 380 randomly selected medical​ students, 21 said that they planned to work in a rural community.…

A: Given that 380 randomly selected medical​ students, 21 said that they planned to work in a rural…

Q: The manager at Bell's Gym wants to know the proportion of members who use the Cardio Machines. A…

A: The objective of this question is to calculate a 97% confidence interval for the proportion of gym…

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: when 282 college students are randomly selected and surveyed, it is found that 109 own a car. find a…

A: It is given that sample size (n) is 282 and x is 109.

Q: Out of 300 people sampled, 171 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: A recent study showed that among 725 randomly selected subjects who completed 4 years of college,…

A: We have given that,  Favorable cases (X) = 139 and Sample size    (n) = 725 Then,  We will find 95%…

Q: Of 400 randomly selected medical students, 21 said that they planned to work in a  rural community.…

A:

Q: A sample of 3048 randomly chosen people found that 341 of them were left-handed. Construct a 99%…

A: Sample proportion=p^=xn=3413048Critical value for 99% confidence interval is=z=2.576n=sample…

Q: andom sample of 1200 high school freshmen was taken and it was found that 559 of them were reading…

A: The population proportion (p) will be proportion of high school freshman who reads at or above their…

Q: A survey of 300 women shoppers found that 17% of them shop on impulse. What is the 80% confidence…

A: From the provided information,A survey of 300 women shoppers found that 17% of them shop on impulse.…

Q: In a sample of 300 people, 48 identified as dog owners. Construct a 99% confidence interval for the…

A: Obtain the 99% confidence interval for the true proportion of people who are dog owners. The 99%…

Q: Out of 54 randomly selected patients of a local hospital who were surveyed, 42 reported that they…

A: Given that, The total patients n are 54 and the total patients who were satisfied x are 42.

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.