F= 15N 0 = ? F = 4.5N 2 of 2 A force is applied to a block sliding along a surface (Figure 2). The magnitude of the force is 15 N, and the horizontal component of the force is 4.5 N. At what angle (in degrees) above the horizontal is the force directed? Express your answer in degrees to two significant figures. ▸ View Available Hint(s) 0 = ΕΠΙ ΑΣΦ ?

Situation 4. Determine the magnitude and coordinate direction angles of the resultant force acting on A. 2.5 ft- 3 ft B 4 ft 3 ft y FB= 600 lb 4 ft Fc = 750 lb 21²

Find the Resultant of the following Forces by Component Method.   F₁ = 12 N. West   F₂= 24 N, 30° North of West   F3 = 15 N, 75° South of West   F₁ = 28 N, 50° South of East   Draw the initial and final graphical representation that will illustrate R and show your solution. Find the Resultant of the following Forces by Component Method. F₁ = 12 N. West F₂= 24 N, 30° North of West F3 = 15 N, 75° South of West F₁ = 28 N, 50° South of East Draw the initial and final graphical representation that will illustrate R and show your solution.

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