Answered: *F 0.01 in. - Undeformed - Deformed…

Engineering

Civil Engineering

*F 0.01 in. - Undeformed - Deformed 0.10 in. 0.004 in. FIG. P2.39 0.12 in.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Consider an elastic straight beam of length L = 10n m, with square cross-section of side a = 5 mm,…

Q: 2. It is assumed that the stress-strain relations of isotropic linear elastic- ity, with Young's…

A: Low carbon steel for the most part displays an extremely direct stress–strain relationship up to a…

Q: The thin bar is subjected to an increase in temperature along its axis. Determine the end B of the…

Q: The stresses acting on element A in the web of a train rail are found to be 'X (MPa)' tension in the…

A: solution of part (b) Given Data: δx=75 MPaδy=90 MPaτxy=40 MPaθ=10ο calculate the stresses δx acting…

Q: Consider an elastic straight beam of length L = 10r m, with square cross-section of side a = 5 mm,…

A: Given data, L = 10π Side(a) = 5 mm y = 5/2 = 2.5mm= 2.5×10^-3 m E = 200 GPa = 200×10³mpa Maximum…

Q: the change in geometry stress is applied. This is the ratio of the breaking strength of the material…

A: USe stress vs strain graph

Q: normal stresses of 0 and 10 MPa (T)

A: Given:A rod element is oriented orthogonally to the horizontal and verticalσx=0 MPaσy=10 MPaτxy= 6…

Q: In a pure shear condition, the maximum value of shear stress is observed to be 20 MPa element shown,…

Q: 85 In a pure shear condition, the maximum value of shear stress is observed to be 20 MPa for an…

A: Calculate the change in length of diagonal AB?

Q: 11 Strength is a physical property.( 12 True 13 False To be safe, strength of material is less th an…

A: Given that:- 11) Strength is a physical property As we know that size, state of matter, colour,…

Q: The state of plane strain on the element is P x = -300(10-6), P y = 0, and gxy = 150(10-6).…

A: (a) The x component of the strain is ϵx = -300 x 10-6 The y component of the strain is ϵx = 0 The…

Q: Consider a solid shaft is carrying a torque T and an axial load P as shown in Figure 1) Calculate…

A: radius R=20 cm and diameter d=40 cm 400 mmcross section area A=π4×4002=0.1256m2 Normal force…

Q: Consider an elastic straight beam of length L= 10t m, with square cross-section of side a = 5 mm,…

A: To find the maximum bending stress-

Q: o=Fe" is known to be the stress-strain relation of the material during tension and compression.…

Q: 160 MPa 120 MPa

A: Solution:- Major principal stress, σ1=σx+σy2+σx-σy22+τxy2 =σx2+-σy22+τxy2 =1602+-16022+1202…

Q: For the one-dimensional three-node element of length I shown below, derive the element equations if…

A: Step 1

Q: 85 In a pure shear condition, the maximum value of shear stress is observed to be 20 MPa for an…

Q: The The state of stress of an element is given as follows. value of normal stress are = 30MPa, σ, =…

A: Given: The value of normal stress, σx=30 MPaσy=-10 MPa. Major principal stress, σ1=50 MPa.

Q: 8 ksi For the state of stress shown in the figure, determine normal and shearing stresses on the…

Q: The change in length of diagonal AB is un

Q: The state of strain at the point has components of € = 300 (10-). y = -260 (10-6), and Yzy = 460…

Q: • Part A- Orientation of the planes of maximum and minimum normal stress A Learning Goal: To…

A: σx=-22Mpaσy=114Mpaτxy=56MpaRadius of the circleR=(σx-σy2)2+τxy2R=(-22-1142)2+562R=88.09…

Q: The state of stress of an element is given as follows. The value of normal stress are = 30MPa, σ₂ =…

A: Given data, The value of normal stress in x and y axis, σx=30 MPaσy=-10 MPa. Major principal stress,…

Q: 80.7 MPa В. = 71.15" = -18.85 32.7 MPa 77.5 MPа C. = 67.91* -22.09* 25.5 MPa 84.7 MPa D. = 75.11"

Q: 160 MPа 160 MPа, The state of stress at a point is shown on the element. You are required to…

Q: The three equally spaced vertical rods in Fig. (a) are securely attached to a rigid horizontal bar.…

A: Given :

Q: The strain components Ex, Ey, and Vxy are given for a point in a body subjected to plane strain.…

Q: FOR THE ELEMENT SHOWN, DETERMINE THE MAXIMUM NORMAL STRESS AND SHOW IT ON A PROPERLY ORIENTED…

A: Given figure shows a stress element and it is required to find the principle stresses and maximum…

Q: The rectangular plate is subjected to force P that causes elongation in the horizontal direction and…

Q: The state of strain at the point on the leaf of the caster assembly has components of Ex =…

Q: Required information. Consider the given state of stress. Take X= 16 MPa and Y= 48 MPa. Y + X 60 MPa…

Q: A rigid steel bar is supported by three rods, as shown. There is no strain in the rods before the…

Q: An element is subject to the following normal and shear strains: €x = -350 x 10-6 €y = 200 x 10-6…

Q: Using the force (flexibility/compatibility) method, analyse the structure in the figure below: A ΕΙ…

Q: The strain components ɛx, ɛy, and yxyare given for a point in a body subjected to plane strain.…

Q: Use the stress transformation equations to determine the state of stress for the element shown if it…

Q: 9-10 Determine the equivalent state of stress on an element if it is oriented 30° clockwise from the…

A: you can also use σx+σy=σx′+σy′ . if you one of the required stressesif you have any doubts please…

Q: 1- 0.01 in. Undeformed - Deformed 0.10 in. 0.004 in. FIG. P2.39 0.12 in.

Q: If the given element is oriented at an angle of 25° with the x-axis, calculate the stresses acting…

A: Given: σx=110 MPaσy=90 MPaτxy=25 MPaθ=30°

Q: In a pure shear condition, the maximum value of shear stress is observed to be 20 ME element shown,…

Q: Determine principal stress

A: Given data : Normal stress in X direction (σX)=-100 MPaNormal stress in Y direction (σY)=0Shear…

Concept explainers

Solid Mechanics

Engineering mechanics is a branch of science that deals with forces causing bulk motion in bodies and the effect that these forces cause on the bodies. Engineering mechanics does not deal with the internal changes that occur on account of these external forces. The internal effects in a body or a material under the action of external forces are studied in a new branch of science called solid mechanics, the strength of materials, or the mechanical behavior of engineering materials.

Question

The rectangular element is deformed in shear as shown. Find the shear strain.

*F 0.01 in.
- Undeformed
- Deformed
0.10 in.
0.004 in.
FIG. P2.39
0.12 in.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Derive the stiffness matrix and Derive the kincma tic eyutn
The strain components & & and Yxy are given for a point in a body subjected to plane strain. Determine the strain components & Eti and Ynt at the point if the n-t axes are rotated with respect to the x-y axes by the amount and in the direction indicated by the angle 8. Sketch the deformed shape of the element. &x=-1200 μs, &y= 200 με. Vxy = 1400 μrad, and 0 = 30° x Answer: En = Et = Ynt = με με prad
/
A differential element on the bracket is subjected to plane strain that has the following components: , strain at x = 250 x 10-6, strain at y = 300 x 10-6, strain at x y= -500 x 10-6. Use the strain-transformation equations and determine the normal strain strain x' in the x' direction on an element oriented at an angle of 35°. Note, a positive angle is counter clockwise.
When an axial load is applied to the ends of the bar shown in the figure, the total elongation of the bar between joints A and C is 0.19 in. In segment (2), the normal strain is measured as 1,650 pin./in. Determine (a) the elongation of segment (2). (b) the normal strain in segment (1) of the bar. Answers: (a) 8₂ = (b) E₁ = 41 in. (2) 93 in. lin. uin./in. P
The state of strain at the point has components of € = 300 (10-6), y = -260 (10-6), and Yay = 460 (10–6). Figure
xy=53
Rigid bar ABCD is loaded and supported as shown. Steel [E = 29900 ksi] bars (1) and (2) are unstressed before the load P is applied. Bar (1) has a cross-sectional area of 0.81 in.2 and bar (2) has a cross-sectional area of 0.46 in.2. After load P is applied, the strain in bar (1) is found to be 770 με. Assume L1=55 in., L2=78 in., a=31 in., b=31 in., and c=36 in. Determine: (a) the stresses in bars (1) and (2). (b) the vertical deflection vD of point D on the rigid bar. (c) the load P.
16 Yield point is the boundary in the stress-s train diagram where stress loses its prop ortionality with strain.( 17 True 18 False Strain is the ratio deformation over origin al length.( True False The value of stress can be unitless. True False
The strain components EE. and Vxy are given for a point in a body subjected to plane strain. Determine the strain components En. Et and Ynt at the point if the n-t axes are rotated with respect to the x-y axes by the amount and in the direction indicated by the angle 8. Sketch the deformed shape of the element. Ex=-1150 μe, &, = 290 μE. Vxy = 1450 μrad, and 8 = 38° 12 X Answer: {= Ynt = με με urad
Schematically find the normal and shear stresses in the plane when the element given in the form of plane stress is rotated 30 degrees clockwise with the Mohr circle.
answer quickly