Three parallel pipes connected at the two ends have flow-rates Q₁, Q₂ and Q3 respectively,and the corresponding frictional head losses are hL₁, h₁2 and h13 respectively. The correctexpressions for total flow rate (Q) and frictional head loss across the two ends (h₁) are(A) Q = Q₁ + Q₂ + Q3; h₁ h₁1 + hL2 + hL3(B) Q = Q1 + Q2 + Q3; hL=hL1 = hL2=hL3(C) Q = Q₁ Q₂ = Q3; h₁ = hL1 + hL2 + hL3==(D) Q = Q₁ Q2 Q3; h₁ h1 = hL2 = hL3===

Given, 3 parallel pipes connected at two ends have, flow rates= Q1,Q2 and Q3…

Answered: expressions for total flow rate (Q) and…

Engineering

Mechanical Engineering

expressions for total flow rate (Q) and frictional head loss across the two ends (h₁) are

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Explain the major and minor losses? Then solve for the parallel pipes system shown below, a pump is placed in line 2 so that 0.142 m³/s will flow through each pipe. Pipe material is cast iron and for each elbow. Find the relation between the head loses hL1 and h12 and estimate the necessary pump head. Water viscosity is μ=1x10-³ Pa.s. Line 1, L-30 m, D= 6 inches Q₁-0.142 m³/s Pump Line 2, L, 30 m, D-3 inches Q-0.142 m/s R
piping system can be neglected but the minor loss at the exit can't be neglected. What is the total head loss in the system, i.e. free surface to pipe exit? What is the minor loss at the exit? volumetric flow rate at the exit is 0.01 m³/s. Assume the minor loss at the entrance of the The valve is partially open. The pipe is made of commercial steel (ɛ = 0.046 mm). The 4. Water is being discharged from a very large reservoir via the piping system shown below. What is the loss coefficient at the exit? Water p=1000 kg/m3 5 m p=0.001 kg/(m s) 0.1 m Q=0.01 m3/s 25m
Ex ....... HYDRAUE • The pump is to be connected to a rising main which has a diameter (D) of 400 mm and a length of 137 m.The entry exit and minor head losses in the pipeline can be taken as 80D in this particular situation. The friction loss can be approximated by h; = ALQ² / 1 2D5 with A=0.04. The static lift is 10 m. By considering a single pump (P). And two of the pumps in series (P+P) and parallel (P//P) determine: > the H-Q curve of the two pump combinations » Which combination will be capable of discharging at least 0.3 m³/s, with the ability to pump up to 0.35 m³/s if the need arises. %3D
The diagram shown illustrates the flow in a circular metal duct 20 feet long. The duct has a sudden contraction at the inlet and sudden expansion at the outlet. The diameter of the duct is 10 inches and the flow rate is 600 cfm. The duct is such that both ends have area ratio of 0.6. Thus A2/A1 = A3/A4 = 0.6. Calculate:(a) Pressure loss in the duct due to sudden contraction (in. wg.).
I need the answer at 20 minute
Compute the Cross sectional area of Pipe Discahrge=0.8 m3/s Velocity=2 m/s
Which of the following equations below describes the system head of the piping shown below. The total length of the pipe is 154 ft. Take the friction factor to be 0.026. The pipe used has a nominal diameter of 4 inches and Schedule No. 40. The system head H is in ft and the flow rate Q is in ft3/s. a. H = 51 + 25.98(Q^2) b. H = 54 + 24.98(Q^2) c. H = 54 + 25.98(Q^2)
B1. A crude oil of specific gravity 0.75 is flowing through a pipe of diameter 275 mm and the frictional head loss of 5 m of crude oil between the two ends of a pipe which are 525 m apart. Calculate the Reynold's Number, discharge of crude oil in the pipe. Take co - efficient of friction as 0.007 and kinematic viscosity as 10 stokes. (Enter only the values by referring the unit given. Also upload the hand written answers in the link provided) The velocity of flow of oil in the pipe is (m/s) The Reynold's Number for the flow is Discharge of crude oil through pipe (in m3/s) is
The diagram shown illustrates the flow in a circular metal duct 20 feet long. The duct has a sudden contraction at the inlet and sudden expansion at the outlet. The diameter of the duct is 10 inches and the flow rate is 600 cfm. The duct is such that both ends have area ratio of 0.6. Thus A2/A1 = A3/A4 = 0.6. Calculate: Total pressure loss in the duct (in. wg.).
Water at 80°F flows from a storage tank through 618 ft of 6-in Schedule 40 steel pipe, as shown in the figure. Taking the energy loss due to friction into account, calculate the required head hin feet above the pipe inlet to produce a volume flow rate of 1.65 ft³/s. (round the final answer to three significant figures) h 6-in Schedule 40 steel pipe pipe length
Question 6 Determine the velocity of flow and the friction loss as 0.472 m3/s of air flows through 23 m of an 0.305 m-diameter round duct V=6.5 m/s and DeltaP=41.5 Pa V=15.3 m/s and DeltaP=117.5 Pa V=9.3 m/s and DeltaP=94.3 Pa V=6 m/s and DeltaP=11 Pa
The Darcy friction factor for both of the pipes shown is 0.024. the total flow rate is 300 m3/h. what is the flow rate through the 250 mm pipe. 325 m, 150 mm diameter a= 300 m/h 650 m, 250 mm diameter