Express the following signals in terms of singularity functions: vj(t) A 1 -1 -1 a. Singularity Function vz(t) 4 2 0 2 4 b. Singularity Function
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Q: Express the following signals in terms of singularity functions:
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Q: 1. Transient analysis t=0 R2=20 R1=30 V1=45 V (+ R3=60 L=7 mH V2=26 V (+ 0 the switch is The switch…
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Q: 1. Transient analysis t=0 R2=20 R1=30 V1=45 V (+ R3=60 L=7 mH V2=26 V (+ The switch has been open…
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- You are an electrician working in an industrial plant. You discover that the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-volt AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 mF and a voltage rating of 240 VAC. The only 10-mF AC capacitor in the storeroom is marked with a voltage rating of 350 WVDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.A capacitor of capacity C₁ is charged upto V volt and then connected in parallel to an uncharged capacitor of capacity C₂. The final potential difference across each will be (a) (c) C₂V G₁ + C₂ (1+2) GV G + C₂ (4) (1-²) v (b)Please help me to solve this. Thank you
- 6. PLEASE SOLVE AND SHOW YOUR DETAILED SOLUTION WITH FBD. The currents at the junction point in a circuit have the following values I1 = (15 – j4) A and I2 = (12 + j22) A. Calculate I1 + I2.For R1=9000, R2=2000, R3=6000, R4=5000, C1=0.006, C2=D0.002 & 11=0.007 A in the shown circuit, obtain the energy stored in each capacitor under dc conditions. C2 R4 ŽR3 ER2 ŽRI C1= Energy stored in C1= Energy stored in C2=The circuit in Figure has been connected for a long time. If the battery is disconnected, how does it take the capacitor to discharge to 1/20 of its initial voltage? Take R₁ = 2.00 Q, R₂=4.00 Q, R3-7.00 Q, R4 = 2.00 Q and C= 5.00 uF and ε = 14.0 V. (Your result must be in us. Include 2 digit after the decimal point and maximum of 2% of error is accepted in your answer.) E R₂ R₂ BA
- For R1=1000, R2=6000, R3=6000, R4=4000, C1=0.003, C2=0.002 & 1=0.005 A in the shown circuit, obtain the energy stored in each capacitor under dc conditions. C2 H R4 I1(4 ŽR3 ŽRI C1 Energy stored in C1= Energy stored in C2=what are the complex powers of all elements in the circuit?(Sj2π,S-j1π,S2π,S1π,S6Z0*V)In the circuit below, Find the voltage across the inductor at time t = 0.000909 s. The values are V1 = 146V, R = 4.4 ohms, L =0.02 henries
- The figure below shows a simple RC circuit with a 3.30-μF capacitor, a 4.40-M resistor, a 9.00-V emf, and a switch. What are the following exactly 9.00 s after the switch is closed? (a) the charge on the capacitor 13.7204 UC (b) the current in the resistor 0.0110522 x Your response is off by a multiple of ten. HA (c) the rate at which the capacitor is storing energy μW (d) the rate at which the battery is delivering energy μWCan someone explain to me this solution HOW AND WHY? every stepsComplex Numbers - Evaluating a Complex Number with Complex PowerA resistor and a capacitance are connected in series to an emf source. The time constant of the circuit is 0.87 s. What will be the 35 - time constant of the new circuit when another capacitor identical to the first is connected in series with the circuit? O a) 0.973s O B) 1,742 s O C) 2.034 s O D) 2.136 s O TO) 0.435 s