Express the equilibrium constant for the following reaction. CH4(g) +2 O2(g) = CO2(g) + 2 H2O(g) [CH4][02] A) K= [CO2][H2O] [CH4][20212 B) K= [CO2][2H2012 C) K= [CO2][H2012 [CH4][02]² D) K= [CO2][2H2012 [CH4][202]² [CH4][0212 E) K= [CO2][H2012 ○ A) O B) C) D) E)

I had 1.0 mL of 1.0M CoCl2 in a test tube.  I put it into boiling water.  [Co(H2O)6]2+, [CoCl4]2-  Equilibrium temperature effect.  Effect of heat What happens to the equilibrium?  Use this equation in your explanation... 4Cl_ (aq) + [Co(H20)6]2+(aq)---[CoCl4]2-(aq)+ 6 H20 (l) I did this in class.  The color change was very slow but it changed from a burgandy to fushia.

the equilibrium expressions for the following reactions:   2Fe(s)      +        3H2O(g)   ↔        Fe2O3(s)     +    3 H2(g)   A [Fe2O3][H2]      = Keq [Fe][H2O]   B [Fe2O3][H2]3     = Keq [Fe]2 [H2O]3   C [H2]3     = Keq [H2O]3   D   [Fe]2 [H2O]3     = Keq [Fe2O3][H2]3

#9 part E