Express the confidence intervals (70.3%, 87.9%) in the form of p-hat, plus or minus ME. ? Plus or minus ?

Q: Express the confidence interval (11.8 % , 18.6 % ) in the form of p + ME. %

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Q: Express the confidence interval (84.4 % , 95 % ) in the form of p + ME. Question Help: D Video…

A: Given Confidence interval is,Lower limit=84.4%Upper limit=95%Express in form of p±ME

Q: í 600 people sampled, 348 had kids.

A: Given that  Sample size (n) = 600 Had kids (X) = 348   We know that  Best point estimate (p)= xn…

Q: Express the confidence interval (68 % , 79.6 % ) in the form of p + ME.

A: The mid-point of the confidence interval gives the value of p-cap.

Q: A  95% confidence interval for the  proportion of voters who say "they want change" is computed and…

A: From the provided information, Confidence level = 95% Confidence interval for the proportion is…

Q: xpress the confidence interval (48.1% , 64.7%) in the form of (p-hat) +- ME ______%+-______%.…

A: Given Information: Confidence interval for population proportion p is: (48.1% , 64.7%) = (0.481,…

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: The confidence interval was (41%, 45%) What was the margin of error? +/- % What was the summary…

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Q: Express the confidence interval (75.4 % , 87.6 % ) in the form ofp ± E.

A: The confidence interval for a population proportion/percentage is given as follows  (75.4%, 87.6%)…

Q: Express the confidence interval 56.4 % < p < 67.6 % in the form of p ± ME.

A: # Given: confidence interval of population proportion :56.4%&lt;p&lt;67.7%  then write the…

Q: A television station surveys 200 customers and finds that 23% of customers watch the evening news.…

A: Given data n=200 p=23% confidence level=99%

Q: Express the confidence interval (30.6 % , 43.6 % ) in the form of p ± ME. % + %

A: Express the confidence interval (30.6% , 43.6%) in the form of p^±ME.

Q: Express the confidence interval (48.7 % , 58.5 % ) in the form of p ± E.

A: Given information confidence interval (48.7%,58.5%)

Q: A  95% confidence interval for the  proportion of voters who say "they want change" is computed and…

A: For the population proportion, the confidence interval can be computed using the formulae: C.I=p⏞±E…

Q: Express the confidence interval (50.6 %, 56.6 %) in the form of p + E. % +

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Q: Express the confidence interval (76.2%, 93.2%) in the form of p+E. % ± ae

A: Confidence interval=(76.2% , 93.2%)Upper limit=93.2%Lower limit=76.2%

Q: Express the confidence interval (74.6%,82.4%)in the form of ˆp±ME

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Q: Express the confidence interval (68.8 %, 79 %) in the form of p + ME. % ± 96 Question Help: Video…

A: Given CI=(68.8%,79%)

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: Express the confidence interval 85.8 % ± 3 % in interval form. Write you answer in DECIMAL form.…

A: From the provided information, Confidence interval is 85.8% ± 3%

Q: Express the confidence interval (45.7 % , 59.5 % ) in the form of p + ME.

A: From the provided information, Confidence interval is (45.7%, 59.5%)

Q: press the confidence interval (81.8%,96.4%)(81.8%,96.4%) in the form of ˆp±E.

A: Given: Lower limit = 81.8% = 0.818  Upper limit = 96.4% = 0.964 The point estimate can be calculated…

Q: Express the confidence interval (75.7 % , 86.5 % ) in the form of p + E. %土

A:

Q: Commerce students were asked if they watch or listen to the state of the nation address (SONA), of…

A: Given: n= 220 ,x= 105 At 90.0 % confidence level , z score= 1.645 Need to find confidence interval…

Q: To assess the proportion of the readers of a magazine being professional, a random sample of 1000…

A: Given that the random sample of 1000 readers is selected and 660 are found to be professionals. That…

Q: A researcher wants to estimate the actual proportion of citizens of a certain country who feel that…

A:

Q: In a recent poll, 289 people were asked if they liked dogs, and 17% said they did. Find the margin…

A: Let X be the number of people who liked dogs Given: Number of people or sample size (n) = 289…

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A: A uses "chance," not confidence, and is wrong. B if that is truly B, is not correct. 99% of the…

Q: Express the confidence interval 12.3 % +7 % in interval form.

A: The confidence interval is 12.3%±7%.

Q: Express the confidence interval (79.7%, 93.5 %) in the form of p + ME. % ± %

A: The confidence interval is (79.7% , 93.5%)Lower confidence limit=79.7%Upper confidence limit=93.5%

Q: A firm randomly samples 100 workers at its New York plant and finds that 32% of the workers say that…

A: The proportion of workers who say that they buy the firm’s product is 0.32.

Q: In a survey 2 of 1000 US adults, 20% say they never exercise. Construct a 99% confidence interval…

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Q: What happens to the spread of an interval if you increase the confidence level from 90% to 99%?

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Q: Explain "Plus Four" Confidence Interval for p

A: There are a number of issues that must be addressed when constructing confidence intervals for…

Q: A poll showed that 385 out of 700 adults said they would be interested in traveling to outer space…

A: This question requires accurate results, Hence I will use excel to solve this question.…

Q: In a recent poll, 150 people were asked if they like dogs, and 40% said they did. Find the margin of…

A:

Q: What is the lower endpoint of a 95% confidence interval for the percent of students who like online…

A: Given Level of significance ɑ=0.05, x=92, n=134

Q: Express the confidence interval 0.372 + 0.035 in interval form. You may use (lower, upper) or…

A: The confidence interval is given as 0.372 ± 0.035.

Q: Z-score for an 88% confidence level

A: The objective of the question is to find the Z-score for an 88% confidence level. The Z-score, also…

Q: Express the confidence interval (70.4%,80.4%) in the form of ˆp±ME

A: It is given that the confidence interval is (70.4%, 80.4%).

Q: FIND Za2 FOR THE 99.50 CONFIDENCE INTERVAL

A: Find α/2Level of Confidence = 99.5%α = 100% - (Level of Confidence) = 0.5%α/2 = 0.25% = 0.0025

Q: you want to find out the percent of people who use an iPhone so you survey 120 random adults of whom…

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.