Express the confidence interval 46.7%±5.1%46.7%±5.1% in interval form.
Q: find x squarea/2,df and xsquare 1-a/2,df for confidence level 80%, and n = 45
A: The sample size is, n = 45. The level of significance is, The degree of freedom is,
Q: Express the confidence interval 8.5%<p<25.3% in the form of p±ME.
A: Solution: From the given information, the confidence interval for the population proportion is…
Q: Express the confidence interval 57.7%±9%57.7%±9% in interval form.
A: Given Information: Confidence interval = (57.7% ± 9%)
Q: Express the confidence interval (0.082,0.156) in the form of p−E<p< p+E.
A: We know 100(1-α) % confidence interval for true proportion is, C.I. = [p-E, p+E] where, p - sample…
Q: A random sample of 75 sales employees work an average of ?̅ = 40 hours per week in a company. Assume…
A: Given information Sample size, n = 75 Sample mean, x-bar = 40 hours Population standard deviation, σ…
Q: If n=130 and p (p-hat) =0.53, find the margin of error at a 99% confidence level Give your answer to…
A: The sample size is .The sample proportion is .The confidence level is .
Q: Express the confidence interval 22.5%<p<33.7% in the form of ˆp±ME. % ± %
A: The given confidence interval is (22.5%, 33.7%). Here, upper limit is 33.7 and lower limit is 22.5.
Q: You collect a random sample of 73 webpage load times in milliseconds (ms) from the server logs. The…
A: The sample mean is 104, sample standard deviation s 32.4, and sample size is 73. The degrees of…
Q: You collect a random sample of 70 webpage load times in milliseconds (ms) from the server logs. The…
A: Given that, The degree of freedom is, df=n-1 =70-1 =69 Critical value: Using the t-table, the…
Q: A scientist claims that only 67% of geese in his area fly south for the winter. He tags 70 random…
A: The scientist's hypothesis as: H0: p=0.67 H0: p≠0.67 Calculate the sample proportion as follows :…
Q: Express trle 0.000
A: Solution: The given confidince interval is 0.666 < p < 0.888 Lower limit = 0.666 Upper limit…
Q: If n=100 and p' (p-prime) = 0.18, construct a 99% confidence interval. Give your answers to three…
A: Givenn=100p^=0.18confidence interval = 99%
Q: A sample of 36 men has a mean weight of 175 pounds with a sample standard deviation of 13 pounds.…
A: It is given that sample mean is 175 and standard deviation is 13.
Q: Express the confidence interval (0.050,0.112)in the form of p−E<p<p+E.
A: From the given information, the confidence interval is (0.050, 0.112) p = (Upper bound + lower…
Q: If n=330 and p (p-hat) =0.92, find the margin of error at a 99% confidence level Give your answer to…
A:
Q: Express the confidence interval 48.9%±8.8%48.9%±8.8% in interval form.
A:
Q: Express the confidence interval (45.3%,59.3%)(45.3%,59.3%) in the form of ˆp±MEp^±ME. % ± %
A: The margin of error is, Thus, the margin of error is 0.07.
Q: 3- What is the confidence level for the interval ± 1.52- 1.52?
A: Given thatHere, the critical value is 1.52.
Q: Express the confidence interval 27.1%±8.5%27.1%±8.5% in interval form.
A: The given confidence interval is 27.1%±8.5%.
Q: ollect a random sample of 88 webpage load times in milliseconds (ms) from the server logs. The…
A: As the population standard deviation is unknown the critical value from student t distribution at…
Q: Express the confidence interval (0.0847, 0.1530) in the form p± E
A: given data, confidence interval (0.0847, 0.1530)here we have to express the confidence interval in…
Q: Express the confidence interval 30.7 % <p< 43.5 % in the form of p + E.
A:
Q: Express the confidence interval (0.412,0.789) in the form of
A: Confidence interval is an interval estimate which is calculated form the sample data. Confidence…
Q: Express the confidence interval 0.444<p<0.888 in the form p+ E.
A: Obtain the point estimate of the proportion. The point estimate of the proportion is obtained…
Q: If n=360 and p (p-hat) =0.29, find the margin of error at a 95% confidence level Give your answer to…
A: Given that : Sample size (n) = 360 P(hat) = 0.29 Confidence interval is 95% We use here, Margin of…
Q: Express the confidence interval (19.1%,34.5%)(19.1%,34.5%) in the form of ˆp±Ep^±E. . % ± .…
A: The confidence is in the form: (Lower limit, Upper limit) Hence, Plug in all the values in the…
Q: Express the confidence interval 563.8
A:
Q: Express the confidence interval 64.4%±4.1%64.4%±4.1% in interval form.
A: Solution
Q: Express the confidence interval ( 66.9 % , 73.3 % ) ( 66.9 % , 73.3 % ) in the form of ˆ p ± E p ^ ±…
A: Solution-: Given: The C.I. is (66.9%, 73.3%) We express given C.I. in the form of p^±E
Q: Express the confidence interval 44.1%±7.6%44.1%±7.6% in interval form.
A:
Q: If n = 300 and p (p-hat) = 0.8, construct a 99% confidence interval. What is the margin of error?…
A:
Q: Express the confidence interval(0.026,0.088)in the form of p−E<p<p+E.
A: Solution: From the given information, the confidence interval for the population proportion is…
Q: Express the confidence interval 74.1%±4.2%74.1%±4.2% in interval form
A: Express the confidence interval 74.1%±4.2%74.1%±4.2% in interval form
Q: For each confidence interval procedure, provide the confidence level. (Round the answers to the…
A: Since you have posted a question with multiple sub-parts, we will solve first three subparts for…
Q: Express the confidence interval 27.3%±8.3%27.3%±8.3% in interval form.
A: Given that, Confidence Interval = 27.3% ± 8.3%
Q: If n=130 and ôp (p-hat) =0.93, find the margin of error at a 99% confidence level Give your answer…
A: Here, the margin of error for proportion p^ is to be calculated. The formula is given by, z*p^1-p^n,…
Q: Express the confidence interval 50.3% ± 7.
A: Given that The confidence interval is, 50.3% ± 7.9%
Q: Express the confidence interval 71.5%±6.9%71.5%±6.9% in interval form.
A: Confidence Interval: Confidence interval is the interval estimate of the population parameter. It is…
Q: Express the confidence interval 0.814 +0.058 in open interval form (i.e., (0.155,0.855)).
A: Confidence interval : C.I = [0.814 ± 0.058] Confidence interval is the range of values , which gives…
Q: Express the confidence interval 0.784 ± 0.049 in open interval form (i.e., (0.155,0.855)).
A: Given Confidence interval is 0.784±0.049.
Q: For each confidence interval procedure, provide the confidence level. (Round the answers to the…
A: The objective of the question is to determine the confidence level for each of the given confidence…
Q: If n = 140 and p (p-hat) = 0.8, construct a 95% confidence interval. %3D Give your answers to three…
A: We want to find the 95% CI for population proportion
Q: Express the confidence interval (0.412,0.789) in the form of ?̂±
A:
Q: You collect a random sample of 75 webpage load times in milliseconds (ms) from the server logs. The…
A:
Express the confidence interval 46.7%±5.1%46.7%±5.1% in interval form.
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- Express the confidence interval 5.4 % < p < 15.2 % in the form of p + E. % ±Express the confidence interval 148.9±50.9 in interval form.Express the answer in either decimal format or as percents.Express the confidence interval 0.856±0.084 in open interval form (i.e., (0.155,0.855)). ___________________________
- Express the confidence interval (0.017,0.095) in the form of p-EExpress the confidence interval (35,59) in the form of sample mean ± ME.An administrator at Milpitas High School would like to estimate, with 95% confidence, the percentage of students who will enroll in summer courses. Based on a random sample of data that is gathered, a 95% confidence interval is constructed. The interval is 15% ± 3%. If there are 2400 students who attend Milpitas High School, and if the administrator is estimating, with 95% confidence, that 15% ± 3% of these students will enroll in summer courses, this means the possible number of students who might enroll in summer courses is fromConstruct the 9292% confidence interval estimate of the population proportion ?p if the sample size is ?=200n=200 and the number of successes in the sample is ?=118.x=118. <?<<p<Express the confidence interval (0.056,0.124) in the form of P-EExpress the confidence interval 80.1%±3.4%80.1%±3.4% in interval form.SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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