Express the confidence interval 17.1%±3.7%17.1%±3.7% in the form of a trilinear inequality. %

Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence interval for a sample of size 309 with 225 successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. ________ < p < _________

Express the confidence interval 35.1 % ± 6.7% in the form of a trilinear inequality. %

The result of an anthropology test was collected, and the grades and gender are summarized below ABCTotalMale183223Female1719844Total35221067 Let p represent the proportion of all male students who would receive a grade of A on this test. Use a 90% confidence interval to estimate p to three decimal places. Enter your answer as a tri-linear inequality using decimals (not percents). < p<

Manual Transmission Automobiles In a recent year, 6% of cars sold had a manual transmission. A random sample of college students who owned cars revealed the following: out of 124 cars, 29 had manual transmissions. Estimate the proportion of college students who drive cars with manual transmissions with 95% confidence. Round intermediate and final answers to at least three decimal places.

Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval for a sample of size 161 with 74% successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places.

Let pp represent the percentage of all female students who would receive a grade of B on this test. Use a 90% confidence interval to estimate pp to three decimal places.Enter your answer as a tri-linear inequality using decimals (not percents).

Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence interval for a sample of size 169 with 82% successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places._______ < p < _______

Express the...

Construct a 90% confidence interval, using the inequality d-t. To test the effectiveness of a new drug that is reported to increase the number of hours of sleep patients get during the night, researchers randomly select 13 patients and record the number of hours of sleep each gets with and without the new drug. Patient Sleep without the drug 3.6 1.9 2.4 3.7 4.8 4.5 2.9 4.9 4.5 2.3 2.3 3.5 3.6 Sleep using the drug 12 3 4 56 7 89 10 11 12 13 D 4.7 3.1 3.2 4.4 5.4 5.4 3.6 6.8 6.6 4.0 4.9 5.6 4.8 Calculate d for each patient by subtracting the number of hours of sleep with the drug from the number without the drug. The confidence interval is