Express the confidence interval (0.037,0.091)in the form of ^p−E

According to statistics released by CNBC, the number of vehicles that are not insured is staggering. CNBC's sample results indicate that 44 out of 80 vehicles were uninsured. Give a 95% confidence interval for the population proportion of the form p^ ± E where p^ is the point estimator of the proportion and E is the margin of error. Select one: a. The interval is 0.450 ± 0.109. b. The interval is 0.550 ± 0.143. c. The interval is 0.450 ± 0.091. d. The interval is 0.550 ± 0.091. e. The interval is 0.550 ± 0.109.

df=20  confidence interval = 0.90  find out a critical value for left and right tailed test

If n = 300 and ˆpp^ (p-hat) = 0.95, construct a 99% confidence interval.Give your answers to three decimals <p<

If n = 520 and ˆpp^ (p-hat) = 0.55, construct a 90% confidence interval.Give your answers to three decimals                < p <

I have been struggling to solve this problem but I could not figure out what formula or any kind of equations that will help me solve the problem (If n=470 and ˆpp^ (p-hat) =0.83, find the margin of error at a 95% confidence level).

Also compute a 95% confidence interval, Cohen's D, and r^2

If n = 320 and ˆpp^ (p-hat) = 0.45, construct a 90% confidence interval.Give your answers to three decimals    < p <

Of 55 bank customers depositing a check, 20 received some cash back. (a) Construct a 90 percent confidence interval for the proportion of all depositors who ask for cash back. (Round your answers to 4 decimal places.) The 90% confidence interval is from to (b) May normality of p be assumed? O Yes O No < Prev 10 of 10 叩^@G to search