Express 0.15 +0.056 in the form of a trilinear inequality.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Problem 1P
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![**Problem Statement:**
Express \( 0.15 \pm 0.056 \) in the form of a trilinear inequality.
**Solution Structure:**
We need to convert the expression \( 0.15 \pm 0.056 \) into a trilinear inequality of the form:
\[ a < p < b \]
**Calculations:**
1. **Lower Bound:**
\[
0.15 - 0.056 = 0.094
\]
2. **Upper Bound:**
\[
0.15 + 0.056 = 0.206
\]
**Resulting Inequality:**
The trilinear inequality is:
\[ 0.094 < p < 0.206 \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F872b6c9e-2fcf-4b9e-96ef-3fd5bb9956d7%2F7d7faf5a-756d-4935-a77c-d72be74e8d2f%2Fsd42dki_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Express \( 0.15 \pm 0.056 \) in the form of a trilinear inequality.
**Solution Structure:**
We need to convert the expression \( 0.15 \pm 0.056 \) into a trilinear inequality of the form:
\[ a < p < b \]
**Calculations:**
1. **Lower Bound:**
\[
0.15 - 0.056 = 0.094
\]
2. **Upper Bound:**
\[
0.15 + 0.056 = 0.206
\]
**Resulting Inequality:**
The trilinear inequality is:
\[ 0.094 < p < 0.206 \]
Expert Solution
Step 1
Solution:
From the given information, the confidence interval for the population proportion is 0.15±0.056.
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