Explain why each of the following statements is incorrect. a. Entropy increases in all spontaneous reactions. Olt's not the entropy of system, but the entropy of universe, that increases in all spontaneous reactions. Olt's incorrect because entropy decreases in all spontaneous reactions. OIt's not the entropy of system, but the entropy of surroundings, that increases in all spontaneous reactions. b. Reactions with a negative free energy change (A,G < 0) are product-favored and occur with rapid transformation of reactants to products. O4,G° tells only about equilibrium state, not about the rate it establishes. Off A,G° is rather close to zero (but still negative), the transformation won't be rapid. Reactions with a negative free energy change are reactant-favored. c. All spontaneous processes are exothermic. Endothermic processes with negative entropy change can also be spontaneous. All spontaneous processes are endothermic. Endothermic processes with positive entropy change can also be spontaneous. d. Endothermic processes are never spontaneous. O Endothermic processes with positive entropy change are never spontaneous. OEndothermic processes with negative entropy change are always spontaneous. O Endothermic processes with positive entropy change can be spontaneous at high temperatures. O Endothermic processes with negative entropy change can be spontaneous at high temperatures.

6. Which of the following compounds has the highest entropy at 25°C? A. CO₂ (s) B. CH3CH₂OH (1) C. C₂H6 (g) D. S (s) E. H₂O (1)

Part b-- Standard entropy = 205 J/mol K

A cvg.cengagenow.com Flipgrid | 50ffc. GRLContent Netflix Favorites My Home 3-Day General.. Netflix Content [Review Topics] [References] 2req Use the References to access important values if needed for this question. 2req The free energy change for the following reaction at 25 °C, when [H*] = 7.21×10³ M and [Hg²*]=1.17 M, is 178 kJ: 2req 2H*(7.21×10-3 M) + Hg(1)→ H,(g) + Hg²*(1.17 M) AG= 178 kJ What is the cell potential for the reaction as written under these conditions? s 2req Answer: V ts 2req Would this reaction be spontaneous in the forward or the reverse direction? ots OM) pts 2reg Submit Answer Retry Entire Group 9 more group attempts remaining pts M) pts

6. Who is the proponent of the Gibbs free energy? A. William Friedrich B. Guglielmo Marconi C. William Gibbs D. Janno Gibbs 7. When AG 2H1 (g) if the entropy values for each substance is as follows: H2(g) = 130.6, 12 (s) = 116.7 and HI (g) = 206.3 A. AS = +165.3 J/K B. AS-165.3 J/K C. AS = -41 J/K D. AS = +453.6 J/K 9. What value of Gibbs free energy can we safely predict that the reaction is spontaneous at all temperatures? A. a negative value C. a positive value at a low temperature B. a positive value D. a positive value at a high temperature 10. What will be the value of the entropy change of the system in the reaction: 6CO₂(g) + 6H₂O(g) → C6H12O6(g) + 602(g) ? C. no change D. cannot be determined A. positive B. negative 11. Ozone (03) in the atmosphere can react with nitric oxide (NO): Os(g) + NO(g) -> NO2(g) + O2(g) Calculate the G for this reaction at 25°C. (AH = -199 kJ/mol, AS = -4.1 J/K-mol) A. -198 kJ/mol B. +198 kJ/mol C.-301.5 kJ/mol D. +301.5 kJ/mol 12. Which of the…

a. Calculate ΔH°f for methane (you will need to dust off Hess’s Law for this one, and recall that the heat of formation, ΔH°f , is the amount of energy required to form 1 mol of a substance from the elements under standard conditions- start by writing a balanced equation for this process.). b. From appropriate entropy data, calculate ΔS°f for methane. c. Use the above information to calculate ΔG°f for methane. d. Compare your results from part C with the reported ΔG°f for methane

A) for the reaction MgCo3(s) ---> MgO (s) +CO2 we can say that it is a reaction a. spontaneous b. not spontaneous c.in balance d. indeterminate B) Which substance in the following pair of compounds must have the highest standard molar entropy? C2H2 (g) or C2H6(g) a.C2H2(g) b.C2H6 c.C2H2=C2H6(g) d. undetermined

Which species do you expect to have the highest molar entropy? a. CH2Cl2 (g) b. NH3 (g) c. N2O5 (s) d. N2H4 (l)

8. You have discovered a new polymer. A monomer is shown below. To better understand its behavior you calculate its theoretical entropy. With careful measurements you find that it can be in 3 positions around the 1st bond in the chain, 2 around the 2nd bond, 1 around the 3rd bond and 3 around the 4th bond. Further, the ring can be in 4 different positions. What is the entropy in units of KB?