Explain the meaning of the following equation. lim f(x) = 8 X-9 - ○ If |x₁ - 9| < |×2 − 9], then |f(x₁) − 8|≤ |f(x2) — 81. - - ○ If |×1 - 9| < |×2 − 91, then |f(x₁) − 8| < |f(x2) − 81. The values of f(x) can be made as close to 8 as we like by taking x sufficiently close to 9. The values of f(x) can be made as close to 9 as we like by taking x sufficiently close to 8. O f(x) = 8 for all values of x. Is it possible for this statement to be true and yet f(9) = 5? Explain. Yes, the graph could have a hole at (9, 8) and be defined such that f(9) = 5. O Yes, the graph could have a vertical asymptote at x = 9 and be defined such that f(9) = 5. No, if f(9) = 5, then lim_f(x) = 5. X-9 No, if lim f(x) = 8, then f(9) = 8. X-9