Experience in non-destructive testing of 7075-T651 aluminum (Sy = 72 ksi, KIC = 22 ksi in1/2) pressurized pipes dictates that the minimum detectable longitudinal crack length is 10 mm. Thus, a longitudinal crack of length 10 mm could escape detection and be present at any time. The pipes transmit a flow of natural gas and the presence of a crack would not alter the internal pressure. What maximum internal pressure would you recommend? Neglect the pipe curvature when determining the stress intensity factor.
Experience in non-destructive testing of 7075-T651 aluminum (Sy = 72 ksi, KIC = 22 ksi in1/2) pressurized pipes dictates that the minimum detectable longitudinal crack length is 10 mm. Thus, a longitudinal crack of length 10 mm could escape detection and be present at any time. The pipes transmit a flow of natural gas and the presence of a crack would not alter the internal pressure. What maximum internal pressure would you recommend? Neglect the pipe curvature when determining the stress intensity factor.
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter8: Centroids And Distributed Loads
Section: Chapter Questions
Problem 8.88P: Compute the surface area of the axi-symmetric domed structure.
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Experience in non-destructive testing of 7075-T651 aluminum (Sy = 72 ksi, KIC = 22 ksi in1/2) pressurized pipes dictates that the minimum detectable longitudinal crack length is 10 mm. Thus, a longitudinal crack of length 10 mm could escape detection and be present at any time. The pipes transmit a flow of natural gas and the presence of a crack would not alter the internal pressure. What maximum internal pressure would you recommend? Neglect the pipe curvature
when determining the stress intensity factor.
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Step 1 Given
The yield strength is .
The inside diameter is .
The thickness of the cylinder
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