Exercise 4.1 If the resultant R for F1, F2, F3 and F4 acts along r-r, find a. magnitude of F4. b. the resultant R. c. the components of F2 along a-a and b-b. Answer: (a) F4 = 38.5 N, (b) R= 12.96 N, (c) Fa-a= 55.5 N and F,-b = 93.4 N

PROBLEM 1: Determine the resultant of the forces shown Horizontal component of resultant. (ANSWER: 0.275 kN) and the Vertical component of resultant. (ANSWER: 0.876 kN) Direction of resultant from horizontal. (ANSWER: 72.577 kN) Horizontal distance of resultant from A. (ANSWER: 2.889 kN)

F1 F2 F3 A b F4 D F5 Consider the following values: - a = 25 m; b 5 m; c = 25 m; d = 5 m; F1 = 4 kN; F2 = 5 kN; F3 = 6 kN; F4 = 7 kN; F5 = 8 kN; a = 30°, 0 = 60° %3D B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 75.8 kN.m b) 32.7 kN.m c) - 14.6 kN.m d) 72.9 kN.m e) 27.1 kN.m - 66.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) - 198.8 kN.m b) 212.7 kN.m c) - 121.6 kN.m d) 98.9 kN.m e) 125.4 kN.m f) -170.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) - 96.7 kN.m b) 251.1 kN.m c) - 114.6 kN.m d) 217.9 kN.m 154.1 kN.m f)-177.7 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 198 kN.m b) 127 kN.m c) – 219 kN.m d) 369 kN.m e) 151 kN.m f) - 171 kN.m Activate V 5] What is the moment of the force F2 about point E? Go to Setting

2. Forces T1, T2, and T3 are acting on the eye bolt. If the magnitudes of T1, T2, and T3 are 330 N, 220 N, and 440 N, respectively, what is the direction of their resultant? a. b. 54.2 deg upward to the right 69.1 deg upward to the right T₂ 60°40° C. d. T3 X 46.2 upward to the left 37.9 upward to the left

I want the answer in 15 minutes, please, and I want it in clear writing