Exercise 3 State the reading of the micrometer screw gauge in the figure below. 5 0 O 2.37 mm O 2.35 mm O 2.35 cm O 1.73 cm 45 Zero error = Therefore, corrected reading 45 40 35 30 Observed reading: The corrected reading in this case should be

1st image: What is the reading on the micrometer? 2nd image: What is the reading on the micrometer?

Plot graphs for the data in Table 2 and determine the minimum and maximum slopes. Substitute the average slope in the equations in the tables and secure values of g. From the minimum and maximum slopes calculate the minimum and maximum values for g and assign the difference divided by 2 as the error. bo In Table 2 gaverage + (gmaximum - gminimum)/2 Compare this with the accepted value of g in each case by completing the information at the bottom of each table. Table 1 Calculational Averaging Method Riser Block Thickness T= ¾ in. = 1.91 x 10 m %3D 2.805 m Distance between leveling screws L = sin0 = T/L = .39° 2d Average Time, tav (s) (m/s²) Distance Traveled d a = 2 t. Tay (m) .0721 .0680 0669 0658 .0682 10.02 2.24% 75 m 4.56 1 1.5m 7.25m 3.00m 8.20 9.55 36 4 Average Accelerations (m/s) Accel. due to gravity, g = a/sin 0 = a (m/s*) % Difference (use estimated local value g = 9.80 m/s) %3D Assume we have errors of 0.1 cm in the values of T and L. Compute the influence of each of these…

The same projectile experiment was conducted as you did in class. A racquet ball rolls down a track, leaves the track at an initial height of 0.961m above floor, with an exit speed Vexit 1.40m/s at an angle exit 7.46°. The landing spot was repeatedly measured for ten times, and the racquet ball's horizontal range data is provided below. Data run = Landing spot (m) 1 2 0.585 0.590 3 4 0.595 0.590 5 6 0.585 0.580 7 0.580 8 = 9 10 0.585 0.580 0.575