Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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Solve Exercise 2.51 and Exercise 2.53 in detail please.
Only attempt the question when you know the right answer.

Definition 2.50. Let X and Y be sets. The product of X and Y, denoted X x Y, is the
set of ordered pairs given by
X × Y := {(x, y) | x € X ^ y E Y}.
Exercise 2.51. Let A, C C X and B, D C Y.
(1) Show that A × B c X × Y.
(2) Prove or disprove: (X \ A) × (Y \ B) = (X × Y)\(A× B). (If disproved, what does
hold?)
(3) Show that (A × B) N (C × D) = (An C) × (BN D).
(4) Can we replace n by U in the above statement? (If not, what does hold?)
Definition 2.52. Let (X, Tx) and (Y, Ty) be spaces. The product topology on X × Y is the
topology generated by the basis
B := {U × V c X × Y | U € Tx ^ V E TY}.
Exercise 2.53. Show that the product topology is well-defined, that is, B in Definition 2.52
is a basis for a topology.
Problem 2.54. Give an example to show that the basis for the product topology on X x Y
is just a basis, and not generally a topology.
Theorem 2.55. Let X and Y be spaces, A с Х, В с Ү, аnd give X x Y the product
topology. The Ах В — Ах В.
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Transcribed Image Text:Definition 2.50. Let X and Y be sets. The product of X and Y, denoted X x Y, is the set of ordered pairs given by X × Y := {(x, y) | x € X ^ y E Y}. Exercise 2.51. Let A, C C X and B, D C Y. (1) Show that A × B c X × Y. (2) Prove or disprove: (X \ A) × (Y \ B) = (X × Y)\(A× B). (If disproved, what does hold?) (3) Show that (A × B) N (C × D) = (An C) × (BN D). (4) Can we replace n by U in the above statement? (If not, what does hold?) Definition 2.52. Let (X, Tx) and (Y, Ty) be spaces. The product topology on X × Y is the topology generated by the basis B := {U × V c X × Y | U € Tx ^ V E TY}. Exercise 2.53. Show that the product topology is well-defined, that is, B in Definition 2.52 is a basis for a topology. Problem 2.54. Give an example to show that the basis for the product topology on X x Y is just a basis, and not generally a topology. Theorem 2.55. Let X and Y be spaces, A с Х, В с Ү, аnd give X x Y the product topology. The Ах В — Ах В.
Expert Solution
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Step 1

Note: As per bartleby instruction when more then one question is given only one has to be answered. Please upload other separately.

(1) The aim is to show that A×BX×Y

Given that, A,CX, B,DY.

Now, it is known that,

A×B=a,b|aA, bB

It is given that,AX, BY.

So, A×BX×Y.

(2) The objective is to show that, X\A×Y\B=X×Y\A×B

This can be written as, 

X\A×Y\B=x,y|xX and xA, yY and yB=x,y|x,yX,Y and x,yA,B

Since xA,yB imply that, (x,y)A×B.

So, X\A×Y\B=X×Y\A×B.

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