Example Exercise 2 Density of a Rubber Stopper A rubber stopper weighing 8.453 g displaces 6.5 mL of water in a graduated cylinder (Figure 2). What is the density of the rubber stopper? Solution: Dividing the mass of the rubber stopper by its volume, we have 8.453 g 1.3 g/mL 6.5 mL In this example, the volume has only two digits. Thus, the density is limited to two significant digits. We will also determine the density of a solid. The volume of any solid object with regular dimensions can be found by calculation. For example, the volume of a rectangular solid object is calculated by multiplying its length times its width times its thickness. BRUCE

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A rubber stopper weighing 8.554 g displaces 7.0 mL of water in a graduated cylinder. Refer to Example Excercise 2 and calculate the density of the solid rubber stopper.

Example Exercise 2 Density of a Rubber Stopper
A rubber stopper weighing 8.453 g displaces 6.5 mL of water in a graduated cylinder
(Figure 2). What is the density of the rubber stopper?
Solution: Dividing the mass of the rubber stopper by its volume, we have
8.453 g
1.3 g/mL
6.5 mL
In this example, the volume has only two digits. Thus, the density is limited
to two significant digits.
We will also determine the density of a solid. The volume of any solid object with
regular dimensions can be found by calculation. For example, the volume of a rectangular solid
object is calculated by multiplying its length times its width times its thickness.
BRUCE
Transcribed Image Text:Example Exercise 2 Density of a Rubber Stopper A rubber stopper weighing 8.453 g displaces 6.5 mL of water in a graduated cylinder (Figure 2). What is the density of the rubber stopper? Solution: Dividing the mass of the rubber stopper by its volume, we have 8.453 g 1.3 g/mL 6.5 mL In this example, the volume has only two digits. Thus, the density is limited to two significant digits. We will also determine the density of a solid. The volume of any solid object with regular dimensions can be found by calculation. For example, the volume of a rectangular solid object is calculated by multiplying its length times its width times its thickness. BRUCE
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