Example: A proton is released from rest at the positive plate of a capacitor. What is the proton's speed when it reaches the negative plate? The capacitor is illustrated below with spacing d=2.1mm. The strength of the electric field is E=4.5x104N/C. F/₁ proton + d=2.1mm Q [6.26] First off, note that the acceleration x component is negative because it points to the left so ax=-qE/m. We choose the velocity squared equation above because we want to solve for the final velocity (and we are not given the time interval): 2Eqxj v²f = vi + 2ax (xƒ — xi) = 0 - 2Eq(x-x₁) m m Where we made x-0 such that xF-0.0021m and that the proton starts at rest so vx-0. We have to take the square root to get the final speed: 2Eqx Vrf = ± √ m And substituting the numbers we get 4.5 × 10¹N -2( C U₂f = ± √ -)(1.602x10-19C) (-0.0021m) 1.67x10-27kg = ±1.35 x 105 m/s Notice that the sign underneath the radical is positive (as required) and to get the rect velocity component we need to choose the negative sign (moving to the left). The electron is moving extremely fast in this case because typical fields (like in an old TV set) are on this order (around 105 N/C). Question 7 ✪ Homework Unanswered For the example above, how long (in nanoseconds) does it take the proton to travel the distance of 2.1mm between the plates? (Hint: use one of the kinematics equations.) Type your numeric answer and submit TERVE

Part A and B

An alpha particle with a kinetic energy of 7.00 MeV makes a head-on collision with a gold nucleus at rest. Part A What is the distance of closest approach of the two particles? (Assume that the gold nucleus remains stationary and that it may be treated as a point charge. The atomic number of gold is 79, and an alpha particle is a helium nucleus consisting of two protons and two neutrons.) Express your answer in meters. d = Submit VE ΑΣΦ Provide Feedback Request Answer ? m

ℓ = 9 cm, and Q = 3 μ C. Calculate the potential energy of the right-side charge, in Joules. Please be careful of units.  If you blow off units, you will get a wrong answer, and the system will count it wrong.   Diagram is attached.

A uniform electric field with a magnitude of 1200 N/C points in the negative x direction as shown in the figure below. (a) What is the difference in the electric potential between points A and B? (b) What is the difference in the electric potential between points B and C? (c) What is the electric potential difference between points C and A? (d) Is it possible to determine the electric potential at point A or not? Explain your answer. E [1] 3.0 cm A B 4.0 cm 5.0 cm C y "L. X

A parallel-plate capacitor has a charge Q and plate separation d, as shown below. We assume that the size of plates is much larger than the separation d. Each particle is initially at rest and then released, allowing it to accelerate.  Assuming each particle has the same mass, rank the speeds of the particles when they impact the left plate. 1. A parallel-plate capacitor has a charge Q and plate separation d, as shown below. We assume that the size of plates is much larger than the separation d. Rank the force that each particle feels at its given position within the capacitor. E>D=C>A=B D>E>B=C>A D>B>E>C>A A>E>C>D>B E>A=C>D=B   2. A parallel-plate capacitor has a charge Q and plate separation d, as shown below. We assume that the size of plates is much larger than the separation d. Each particle is initially at rest and then released, allowing it to accelerate.  Assuming each particle has the same mass, rank the speeds of the…