
Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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Solve this whole problem and include the interpolation of the same table.

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Example 7.5-3
Solution
391 of 695
Energy Balance on a Steam
JESTITIS
JUTERIIS TULIT, JORING
JUTE Iing for
Now consider the properties at 10 bar and 20 bar. both at a temperature of 400°C. Even though
the pressure has doubled, the values of Û and Ĥ change by much less than 1%. Similar results would
be obtained for liquid water. The conclusion is that when you need a value of Û or Ĥ for water (or for
any other species) at a given T and P, you must look it up at the correct temperature-interpolating if
necessary but you don't have to find it at the exact pressure.
The next example illustrates the use of the steam tables to solve energy balance problems.
eam Tur
Turbine
Steam at 10 bar absolute with 190°C of superheat is fed to a turbine at a rate m = 2000 kg/h. The turbine
operation is adiabatic, and the effluent is saturated steam at 1 bar. Calculate the work output of the turbine in
kilowatts, neglecting changes in kinetic and potential energy.
372 CHAPTER 7 Energy and Energy Balances
OD
The energy balance for this steady-state open system is
Q Search
(Why was the heat term dropped?)
Inlet Steam:
Table B.7 indicates that steam at 10 bar is saturated at 180°C (verify), so that the inlet steam temperature is
180°C + 190°C = 370°C. Interpolating in the same table,
Ĥin (10 bar, 370°C) = 3201 kJ/kg
W₁ = AH = m(Ĥout - Ĥin)
Outlet Steam:
From either Fable B. 6/0 B.7, you can find that the enthalpy of saturated steam at 1 bar is
Hout (1 bar, saturated) = 2675 kJ/kg/
2000 (2675 32014-1
H
1h
{
J
ENG
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