Example 2.A Width is 1 m. Find: F and the position that the fluid pressure exerted. ΣF=0=Fy-Fy - W FH -2 m Fv tw Fx F 4m y Fy=pA = 9810*4*2*1 = 78.5 kN π 2 W = WV = y = y₁² 4 = 9810*0.25 **4*1 = 30.8 kN F₁ = 30.8+78.5 y F₁ = 109.3 KN *1 ΣF=0=FH-Fx Fx = PA X = 5*9810*2*1 Fx = 98.1kN

Hello, thank you for your time. I prefer solutions that emphasize the calculations and final results, rather than extended explanations. As a student, it’s essential for me to see the step-by-step process with equations and values so I can learn from the methods. I appreciate your understanding. With that in mind, please provide a detailed handwritten solution, ensuring each step is accurate by double-checking everything. Carefully review the images to ensure no important details are overlooked.

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