Example 12.3. A small reservoir has a spillway crest elevation 200.0 m. Above this elevation, the storage and outflow from the reservoir can be expressed as: Storage: S=36000+ 18000y m³, Outflow Q=10y m³/s, where y is height of water above spillway crest in m. Route an inflow hydrograph which can be approximated by a triangle as: 1=0 at t=0, 1=30 m³/s at t=6 h and I = 0 at f= 26 h Assume at t=0.y=0 and use At = 2h

The storage in the reach of a stream has been studied. The values of x and K in Muskingum equation have been identified as 0.28 and 1.6 days. If the inflow hydrograph to the reach is as given below, compute the outflow hydrograph. Assume the outflow from the reach at 1 = 0 as 3.5 m³/s. Time (h) Inflow (m³/s) 6 12 18 24 30 35 55 92 130 160 140

Estimate the water influx constant (B) for the following bottom-water-drive reservoir. Boundary pressure (at WOC) and water influx history data are as follows. Time (days) Boundary (psia) Cumulative Influx (1000RB) 30 60 90 120 150 180 210 240 pressure 3000 2956 2917 2877 2844 2811 2791 2773 2755 Water | 0 79 282 570 930 1354 1810 | 2287 2786 The reservoir is circular and has an approximate radius of 2000 ft. Other pertinent aquifer data include r,→, R = 2000 ft , h = 200 ft, k H= 50 md, k,= 2 md, µ = 0.395 cp, ¢ = 0.1, and c, = 8×10-6 psi!.

Water flows in a rectangular channel at a depth of 1.5 m. A 30 cm high smooth hump produces a drop of 15 cm in the water surface elevation. Neglecting losses, estimate the discharge per unit width of the channel. Solution: Refer to Figure 2.18. Let suffixes 1 and 2 refer to sections upstream of the hump and on the hump respectively as indicated in the figure. Energy Line V Е, У, 1 0.15 m √₂ Hump AZ = 0.30 m 2