Example 11.11. An open belt drive connects two pulleys 1.2 m and 0.5 m diameter, on parallel shafts 4 metres apart. The mass of the belt is 0.9 kg per metre length and the maximum tension is not to exceed 2000 N.The coefficient of friction is 0.3. The 1.2 m pulley, which is the driver, runs at 200 r.p.m. Due to belt slip on one of the pulleys, the velocity of the driven shaft is only 450 r.p.m. Calculate the torque on each of the two shafts, the power transmitted, and power lost in friction. What is the efficiency of the drive?

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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3) 23.82 = 9670 W = 9.67 kW Ans.
Example 11.11. An open belt drive connects two pulleys 1.2 m and 0.5 m diameter, on
parallel shafts 4 metres apart. The mass of the belt is 0.9 kg per metre length and the maximum
tension is not to exceed 2000 N.The coefficient of friction is 0.3. The 1.2 m pulley, which is the driver,
runs at 200 r.p.m. Due to belt slip on one of the pulleys, the velocity of the driven shaft is only 450
r.p.m. Calculate the torque on each of the two shafts, the power transmitted, and power lost in
friction. What is the efficiency of the drive?
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Transcribed Image Text:3) 23.82 = 9670 W = 9.67 kW Ans. Example 11.11. An open belt drive connects two pulleys 1.2 m and 0.5 m diameter, on parallel shafts 4 metres apart. The mass of the belt is 0.9 kg per metre length and the maximum tension is not to exceed 2000 N.The coefficient of friction is 0.3. The 1.2 m pulley, which is the driver, runs at 200 r.p.m. Due to belt slip on one of the pulleys, the velocity of the driven shaft is only 450 r.p.m. Calculate the torque on each of the two shafts, the power transmitted, and power lost in friction. What is the efficiency of the drive? e here to search 8: 8 6:20 PM 5/20/202 251 8 W S 3 E C 4 R F 5 T И 6 Y B H & 7 N 1 9 K M O ) O V P -
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