EXAMPLE 10.15 An embankment is shown in Figure 10.29a. Determine the stress increase under the embankment at points A, and A₂. 14 m- 5m 11.5 m- 5 m č A₂ At point A₁ - 14 m 5m 5 m A₂ → 5m → ← 11.5 m At point A₂ H=7m ► 5 m 8 A₁ 5m+¦+ H=7m ► 5 m X A₁ 14 m 16.5 m 5 m 14 m EXAMPLE 10.15 An embankment is shown in Figure 10.29a. Determine the stress increase under the embankment at points A, and A₂. y= 17.5 kN/m² 14 m 16.5 m H A0₂ (1) 5 mq (2.5 m) x (17.5 kN/m³)= 43.75 kN/m2 - Aσ₂ (1) A₂ y= 17.5 kN/m² A₁ 1 122.5 kN/m2 + + T 5m 9=(7 m) x (17.5 kN/m³)= 122.5 kN/m² %= 122.5 kN/m² A₂ 2.5 m ● A0₂ (2) A₁ 14 m- A₂ (2) 9 (4.5 m) x (17.5 - kN/m³)= 78.75 kN/m² A:0) A₂ 14 m 9m ➜ 14 m-

Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN:9781305081550
Author:Braja M. Das
Publisher:Braja M. Das
Chapter6: Vertical Stress Increase In Soil
Section: Chapter Questions
Problem 6.4P: Refer to Figure P6.4. A strip load of q = 900 lb/ft2 is applied over a width B = 36 ft. Determine...
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EXAMPLE 10.15
An embankment is shown in Figure 10.29a. Determine the stress increase under the
embankment at points A₁ and A₂.
14 m-
5m 11.5 m-
5 m
č
A₂
At point A₁
-14 m-
→ 5m → ←
5m
5 m
A₂
11.5 m
At point A₂
H=7m
►
5 m
8
A₁
5m+¦+
H=7m
>·
5 m
X
A₁
14 m
16.5 m
5 m
14 m
EXAMPLE 10.15
An embankment is shown in Figure 10.29a. Determine the stress increase under the
embankment at points A, and A₂.
14 m
16.5 m
y= 17.5 kN/m³
5m9 = (2.5 m)
x (17.5
-
A₂
H
A0₂ (1)
kN/m³) =
43.75 kN/m2
Aσ₂ (1)
y= 17.5 kN/m²
B
A₁
1
90 =
122.5
kN/m2
+
+
T
5m
9=(7 m)
x (17.5
kN/m³)=
122.5 kN/m²
% =
122.5
kN/m²
A₂
2.5 m
→→
● A0₂ (2)
A₁
14 m-
A₂ (2) 9 (4.5 m)
x (17.5
kN/m³)=
78.75 kN/m²
Aar: (33)
A₂
14 m
9 m
➜
14 m
1
Transcribed Image Text:EXAMPLE 10.15 An embankment is shown in Figure 10.29a. Determine the stress increase under the embankment at points A₁ and A₂. 14 m- 5m 11.5 m- 5 m č A₂ At point A₁ -14 m- → 5m → ← 5m 5 m A₂ 11.5 m At point A₂ H=7m ► 5 m 8 A₁ 5m+¦+ H=7m >· 5 m X A₁ 14 m 16.5 m 5 m 14 m EXAMPLE 10.15 An embankment is shown in Figure 10.29a. Determine the stress increase under the embankment at points A, and A₂. 14 m 16.5 m y= 17.5 kN/m³ 5m9 = (2.5 m) x (17.5 - A₂ H A0₂ (1) kN/m³) = 43.75 kN/m2 Aσ₂ (1) y= 17.5 kN/m² B A₁ 1 90 = 122.5 kN/m2 + + T 5m 9=(7 m) x (17.5 kN/m³)= 122.5 kN/m² % = 122.5 kN/m² A₂ 2.5 m →→ ● A0₂ (2) A₁ 14 m- A₂ (2) 9 (4.5 m) x (17.5 kN/m³)= 78.75 kN/m² Aar: (33) A₂ 14 m 9 m ➜ 14 m 1
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