Examine the following half-reactions and select the weakest reducing agent among the substances. Cr(OH)3(s) + 3e-Cr(s) + 3OH-(aq) SnO₂(s) + 2H₂O(l) + 4e¯ ⇒ Sn(s) + 40H-(aq) MnO₂(s) + 4H+ (aq) + 2e- ⇒ Mn²+ (aq) + 2H₂O(l) Hg2SO4(s) + 2e-2Hg(/) + SO4²-(aq) A) Cr(s) B) OH-(aq) C) Sn(s) D) Hg(/) E) Mn²+ (aq) E° = -1.48 V E° = -0.945 V E° = 1.224 V E° = 0.613 V

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**Topic: Identifying the Weakest Reducing Agent from Given Half-Reactions**

Examine the following half-reactions and select the weakest reducing agent among the substances.

1. \( \text{Cr(OH)}_3(s) + 3e^- \rightleftharpoons \text{Cr(s)} + 3\text{OH}^-(aq) \)  
   *Standard Electrode Potential (\(E^\circ\)): -1.48 \, \text{V}*

2. \( \text{SnO}_2(s) + 2\text{H}_2\text{O}(l) + 4e^- \rightleftharpoons \text{Sn(s)} + 4\text{OH}^-( \, \text{aq}) \)  
   *Standard Electrode Potential (\(E^\circ\)): -0.945 \, \text{V}*

3. \( \text{iMnO}_2(s) + 4\text{H}^+(aq) + 2e^- \rightleftharpoons \text{Mn}^{2+}(aq) + 2\text{H}_2\text{O}(l) \)  
   *Standard Electrode Potential (\(E^\circ\)): 1.224 \, \text{V}*

4. \( \text{Hg}_2\text{SO}_4(s) + 2e^- \rightleftharpoons 2\text{Hg(l)} + \text{SO}_4^{2-}(aq) \)  
   *Standard Electrode Potential (\(E^\circ\)): 0.613 \, \text{V}*

**Options:**

A) \( \text{Cr(s)} \)

B) \( \text{OH}^-(aq) \)

C) \( \text{Sn(s)} \)

D) \( \text{Hg(l)} \)

E) \( \text{Mn}^{2+}(aq) \)

**Note:** The weakest reducing agent will have the most positive standard electrode potential (\(E^\circ\)) among the listed species in the half-reactions.
Transcribed Image Text:**Topic: Identifying the Weakest Reducing Agent from Given Half-Reactions** Examine the following half-reactions and select the weakest reducing agent among the substances. 1. \( \text{Cr(OH)}_3(s) + 3e^- \rightleftharpoons \text{Cr(s)} + 3\text{OH}^-(aq) \) *Standard Electrode Potential (\(E^\circ\)): -1.48 \, \text{V}* 2. \( \text{SnO}_2(s) + 2\text{H}_2\text{O}(l) + 4e^- \rightleftharpoons \text{Sn(s)} + 4\text{OH}^-( \, \text{aq}) \) *Standard Electrode Potential (\(E^\circ\)): -0.945 \, \text{V}* 3. \( \text{iMnO}_2(s) + 4\text{H}^+(aq) + 2e^- \rightleftharpoons \text{Mn}^{2+}(aq) + 2\text{H}_2\text{O}(l) \) *Standard Electrode Potential (\(E^\circ\)): 1.224 \, \text{V}* 4. \( \text{Hg}_2\text{SO}_4(s) + 2e^- \rightleftharpoons 2\text{Hg(l)} + \text{SO}_4^{2-}(aq) \) *Standard Electrode Potential (\(E^\circ\)): 0.613 \, \text{V}* **Options:** A) \( \text{Cr(s)} \) B) \( \text{OH}^-(aq) \) C) \( \text{Sn(s)} \) D) \( \text{Hg(l)} \) E) \( \text{Mn}^{2+}(aq) \) **Note:** The weakest reducing agent will have the most positive standard electrode potential (\(E^\circ\)) among the listed species in the half-reactions.
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