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- 8PFE-5 What is the current I, in the circuit ? 6ej2t +1 -j1Q IoDetermine the DC currents (B. Ic and le) and de juncion voltages (VBE, VCE and Vca) mA. Ic ma, E mA VBE= V. VCE Vand VCB Use 2 decimal places. RB Use the following values: VBB = 3V RB = 4 kQ Rc = 166 0 Vcc = 19 V BDC = 70 %3D %3D VCC RC VBBFor the circuit shown in Figure Ncc Vee= 22 V, Rc = 5.6kr %3D R8= 330Ks2, B= 80 RB Rc Vi 1.2ksz O.47ks CE ww
- If Is = 1x1016A and V= 26MV, Then Vout is: RL1 k2 3 V 750 mV Q1 Select one: a. None of these O b. 1.31 V O c. 1.65 V d. 2.66 V e. 1.99 V 11:20 PM EN 4/15/2021Q3 shoun in fig los2 15n Sn. 25n 15 RI XL. R2 Xc R3 - 200V, S0HZ-| Calculate: a) The CirCuit Current. b) The Circuit phase Angle- The impedan Ce Voltdrep.Calibri (Body) -11 by AaBbCcDx AaBbCcD AaBbC AaBbCc AaB AaBbCc. mat Painter BIU 1Normal 1No Spaci. Heading 1 Heading 2 Title Subtitle Chang Styles d Font Paragraph Styles IMPEDANCE QUIZ # 2 1. What capacitance when connected in series with a 500Q resistor will limit the current drawn from a 48-mV 465-kHz source to 20µA? * a. 144pF b. 145pF c. 146pF d. 147pF MY ANSWER: c.146pF 2. What is the total impedance at 20kHz of a series circuit consisting of a 1.5mH inductance, a 100Q resistance, and a 0.08uF capacitance? * a. 1340 41.7 b. 1930 L-37.2" C. 920 290 d. 530 2-12.6°
- TE is given as RI-102, Rz=7L, Xes= 10R, Xez=52. XM=6R, Xc=71 in the circuit below. Calculate I. curment and Ve voltage in polar form and mork then the following ilems. in in Angles are given in degr ees. I, JXL1 R2 100/60° jXM -jXc +Vc a) Vo 29.696/17.552 b) Ve 25.870/25.402 Ve 14.702/10.440" d) Vo 27.661/177.887° 1.908,/62 552" 1.805/27,130 4.058/17.003" 21.808/22.713" h) Ve 3.352,/17.887" 2.446/9.456H. W. 3 Determine I, Iç, I, Vne, VeEs and Vea in the Figure below for the following values: R=22KN, R=220N, V=6V, Vc=9V, and Boc=90. Rc VccThe sum of the following two e.m.fs will be e1 = 10 sin wt and e2 = 10 cos wt O 10 O 20 sin wt O 14.14 cos wt O 14.14 sin (wt + TT/4)
- 4. Design the network in the figure to have the following characteristics: i. BW - 500 Hz ii. Qp = 30 iii. Vemax = 1.8 V 0.2 mA Z0° C7 R, = 0 NDC-AC Circuits Express R1 using Rx, Ry, and Rz when performing wye to delta conversion R3 Rx Rz R2 R1 Ry O A. (Rx+Ry)(Ry+Rz)(Rx+Rz) Rx В. RyRz Rx+Ry+Rz O C. Ry+Rz RXRYRZ O D. RXRYRZ Ry+Rz OE. RxRy+RyRz+RXRZ RxThe average value of the voltage in the given Figure is equal to: Note Vm=5V 6.0V 30.0 Select one: O a. 1.59 V O b. 7.07 V O c. 6.37 Od. 3.54 V Clear my choice 31.5mm
