2-Full Adder CFA) Application for the H.A. are limited. The H.A is no Sufficient for adding more than two one-bit numbers. Full Adder is a logic circuit that can add 3- bit and have two outputs. These outputs are the sum of three bits inputs and the second output is carry of them. The truth table and the block diagram are shown below:- RBC SG -S (sum) 00 0 FA 00 Cin -C (carry out) 0 -Carry input -0-00 - From the truth table:- S=1,2,4,7 = ABC ABC ABC + ABCin =ACBcin+B+ A (Bar+ Bcin) = Ā (B@ Cin) + A(B@Cin) = Ŕ (B @ Cin) + R (B&Cin) S = ABB Cin Co= {3,5,6,7 = = ABCin+ABCin+ ABCin + ABC ABC Cint Cin)+ Cin (AB+AB) = AB+ Ch(AGB) Cin= Cin Co EX:- Design H.A. using Comparators only:- Solution: HA S-AB+ AB- AB B = AØB ] C. AB المعادلات المطلوبة Note: RGI-A AGO=A المحاولات الموجودة Comparator A>B(G)=RB A=B (E)= AB + AB = AGB ATB (L) AB >Aizo =A01=A AI=A Λ ABX AGB- AB+AB S=AB+AB =AO B AB = AB = Co V H.W:- Design F.A, using Comparators only.

Work out vbout and vcout

Employing the characteristic curve in Figure 1 and obtain the design for a voltage divider configuration that has a Q point of ICQ = 5 mA and VCEQ = 8 V. Using VCC = 24 V and RC = 3RE. Find the following: a) Draw the configuration indicating each of the elements b) Determine RC and RE c) Find VE d) Determine VB e) Calculate ? for point Q f) Find R2 if R1 = 24 kΩ