Vr = 233 VEx: a reflex klystron operates under the conditionVo=600V , L=1 mm , Rsh= 15K2 , n=2 or (1тode)4e- = 1.759 x 1011 fr=9 GHz , neglect ßima) Find (Vr) valueb) Find the direct current necessary to give gap voltage 200Vc) Calculate the efficiency

It is given that: Vo=600 VL=1mmRsh=15kΩn=2em=1.759×1011fr=9GHzV2=200V

Ex: a reflex klystron operates under the condition 3 Vo=600V , L=1 mm , Rsh= 15KN , n=2 or (1 mode) 4 = 1.759 × 1011 fr=9 GHz , neglect ßi e - a) Find (Vr) value b) Find the direct current necessary to give gap voltage 200V c) Calculate the efficiency

Ex: a reflex klystron operates under the condition 3 Vo=600V , L=1 mm , Rsh= 15KN , n=2 or (1 mode) 4 = 1.759 × 1011 fr=9 GHz , neglect ßi e - a) Find (Vr) value b) Find the direct current necessary to give gap voltage 200V c) Calculate the efficiency

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Dielectric Breakdown

A dielectric is a material with low electrical conductivity and so is classified as an insulator. Dielectric materials are used to block the flow of electricity through them, allowing them to behave as an insulators. They can also be used to store electric charge or improve capacitance.Dielectrics have no free electrons for conduction because electrons are tightly bound to the nucleus. Because dielectrics contain a small number of electrons for electrical conductivity, they have a dipole. The two primary roles of dielectrics in electrical devices are insulation and electrical energy storage. An electric field polarizes the dielectric, and the polarization of the molecules allows dielectric materials to store charge.

Question

Vr = 233 V
Ex: a reflex klystron operates under the condition
Vo=600V , L=1 mm , Rsh= 15K2 , n=2 or (1
тode)
4
e
- = 1.759 x 1011 fr=9 GHz , neglect ßi
m
a) Find (Vr) value
b) Find the direct current necessary to give gap voltage 200V
c) Calculate the efficiency

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