Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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1. A small steam superheater will be made of 0.75-in. schedule 80 stainless steel pipe which will be
exposed to hot flue gas from a boiler. 50 lbm/h of saturated steam at 320 °F will enter the pipe and
be heated to 380 °F. Assuming that the pipe wall temperature will vary from 375 °F at the steam
inlet to 415 °F at the outlet, calculate the length of pipe required for the super heater
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Transcribed Image Text:1. A small steam superheater will be made of 0.75-in. schedule 80 stainless steel pipe which will be exposed to hot flue gas from a boiler. 50 lbm/h of saturated steam at 320 °F will enter the pipe and be heated to 380 °F. Assuming that the pipe wall temperature will vary from 375 °F at the steam inlet to 415 °F at the outlet, calculate the length of pipe required for the super heater
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Follow-up Question

everything looks great but can u plz solve for h using the appropriate nusselt equation

 

attached 

and thens solve for L 

no need to type out equations just need to make sure value is correct

thanks 

Nu = 0.027 Re0.8 pr¹/3 (μ/w) 0.14
A = πD;L
As
πDi
L
=
=
Nu
N₂ = 0.027 (30428.83)0.8 (0.98)3 =
Btu. ft
(0.02
(0.0227 h. ft²°F)
(0.06183ft)
msCp (Te Ti) = hA,ATm
(50m)
b) (0.608 Bor) (380 - 320°F) = h(1.273ft²)(44.2492°F)
lb°F,
=
h
(Ⓒ)
(2.34)
expand button
Transcribed Image Text:Nu = 0.027 Re0.8 pr¹/3 (μ/w) 0.14 A = πD;L As πDi L = = Nu N₂ = 0.027 (30428.83)0.8 (0.98)3 = Btu. ft (0.02 (0.0227 h. ft²°F) (0.06183ft) msCp (Te Ti) = hA,ATm (50m) b) (0.608 Bor) (380 - 320°F) = h(1.273ft²)(44.2492°F) lb°F, = h (Ⓒ) (2.34)
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Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question

everything looks great but can u plz solve for h using the appropriate nusselt equation

 

attached 

and thens solve for L 

no need to type out equations just need to make sure value is correct

thanks 

Nu = 0.027 Re0.8 pr¹/3 (μ/w) 0.14
A = πD;L
As
πDi
L
=
=
Nu
N₂ = 0.027 (30428.83)0.8 (0.98)3 =
Btu. ft
(0.02
(0.0227 h. ft²°F)
(0.06183ft)
msCp (Te Ti) = hA,ATm
(50m)
b) (0.608 Bor) (380 - 320°F) = h(1.273ft²)(44.2492°F)
lb°F,
=
h
(Ⓒ)
(2.34)
expand button
Transcribed Image Text:Nu = 0.027 Re0.8 pr¹/3 (μ/w) 0.14 A = πD;L As πDi L = = Nu N₂ = 0.027 (30428.83)0.8 (0.98)3 = Btu. ft (0.02 (0.0227 h. ft²°F) (0.06183ft) msCp (Te Ti) = hA,ATm (50m) b) (0.608 Bor) (380 - 320°F) = h(1.273ft²)(44.2492°F) lb°F, = h (Ⓒ) (2.34)
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