Evaluate the trigonometric unit: limit as x  --> 0      1-cos^2(4x)/16x^2   How do I begin by solving this? what work is shown to find the answer?   Also, How do I solve the following: Limit as x -->0    Sin(4x)/16x I know the answer is 1/4 (lucky guess from simplifying 4/16) but how do you actually solve it?

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