Evaluate the surface integral 1 d.S where o is the portion of the plane z = 4 - 6x – 1y in the first octant. Then // f(x, y, z) dS ·!! 0 0 = sqrt(38) du du

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
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Evaluate the surface integral 1 dS where is the portion of the plane z = 4 − 6x – 1y in the first octant. Then
-
=
f(x, y, z) dS
!!
sqrt(38)
O
du du
Transcribed Image Text:]] Evaluate the surface integral 1 dS where is the portion of the plane z = 4 − 6x – 1y in the first octant. Then - = f(x, y, z) dS !! sqrt(38) O du du
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