Evaluate the iterated integral. (2 +y² +z) dx dy dz -200 2 3 4 +y? +? )dx dy dz = i

Q: Evaluate the iterated integral.

A: Given, ∫12∫13lnxydydxy To evaluate above integration.

Q: Evaluate the iterated integral. 24 (x + y + z) dx dz dy of

A: To find: ∫02∫04∫01x+y+zdxdzdy

Q: Evaluate the triple iterated integral. 2/2 xyz dx dy dz 0/ -1

A:

Q: Evaluate the iterated integral. 8. '1 (x + y + z) dx dz dy

A: When integrating with respect to one variable , take other variable as a constant.

Q: Evaluate the iterated integral. 225-y y dx dy 15 15 225-y y dx dy = %3D

A: Double integration

Q: Evaluate the iterated integral. 8. (++ y + z) dx dz dy

A: We will evaluate the integral one-by-one with respect to x,z and y

Q: Evaluate the iterated integrals. 2 yz b. So So So xyz dx dy dz Jo 0 0

A:

Q: Evaluate the iterated integral. 30 900- y dx dy 30 900-y y dx dy = i

A:

Q: Evaluate the iterated integral. (x + y + z) dx dz dy

A:

Q: Evaluate the iterated integral. IL(1lx – 49)dy dx (11x – 4y) dy dx = i

A:

Q: evaluate the iterated integral.

A:

Q: Evaluate the iterated integral. yz dx dz dy 45 в) 34 47/3 D) 5

A:

Q: dy dr x+ y 33. a dz dy x² + y 34.

A: .

Q: Evaluate the iterated integral: S", Si yz dx dz dy.

A:

Q: Evaluate the iterated integral. 8. 1 6ze dy dx dz 0/

A:

Q: Evaluate the iterated integral. 3 I (* + 5)dy dx 3 8 (x + 5)dy dx = i

A:

Q: Evaluate the iterated integral. 1*y dx dy Ry dx dy =

A: NOTE: Refresh your page if you can't see any equations. .

Q: Evaluate the iterated integral. (x+y+ z) dx dz dy

A: Given tripple integral is ,                                                     ∫09∫04∫01(x+y+z)dx…

Q: Evaluate the iterated integral. 8 (x + 6)dy dx (x+ 6)dy dx = %3D

A:

Q: /2 sin(z + y) dy dz

A: Let,      I=∫0π2∫0π2sin(x+y)dydx

Q: Calculate the iterated integral. IT (20x - 9x?y2) dy dx

A: Here we have to evaluate I=∫02∫1320x3-9x2y2dydx

Q: Evaluate the iterated integral. 16 zy dx dy 16 Py dx dy = i

A:

Q: Evaluate the iterated integral. /2 x. 4 cos (x + y + z) dz dx dy

A:

Q: (4- y? 2 dx dy /4 – y²

A:

Q: Evaluate the iterated integral. (x + y) dy dx

A: We have to solve given double integral

Q: Evaluate the iterated integral. 2 . (x+y+z) dx dz dy

A: The given integral is: I=∫02∫08∫01x+y+zdxdzdy   As we know the Power Rule: ∫xndx=xn+1n+1+C ; n≠-1

Q: Evaluate the iterated integral. IT (10 + 2x2 + oy?) dx dy

A:

Q: Evaluate the iterated integral. 16 3 x²y dx dy 16 3 Py dx dy : i

A:

Q: Evaluate the iterated integral. IIT*+y+z) dx dz dy

A:

Q: Evaluate the iterated integral. 2 *4z [In(x) f Jo xe Y dy dx dz

A:

Q: Evaluate the iterated integral. ||| x*y² + z² dx dy dz 0.

A:

Q: xVx? + y dy dx

A: Answer for the given iterated integral is   6215 -635

Q: Evaluate the iterated integral. SS 5x= dy dz dz = 0 0 0

A: Integration is evaluated by integrating first y then x then z.

Q: Evaluate the iterated integral. 1 2r y 8ry: dz dy dx

A:

Q: Evaluate the triple iterated integral. r2 xyz dx dy dz

A:

Q: Calculate the iterated integral. '64 Y)dy dx

A: Given that a double integration and we solve this using general rule of integration. Here i attached…

Q: Evaluate the iterated integral. /2 y/6 3/y sin y dz dx dy

A:

Q: 2+ y²) dz dy

A:

Q: Calculate the iterated integral. (x + y)² dx dy

A: In the question we have to find integral of the given function.

Q: Evaluate the triple iterated integral. 2 4 xyz' dx dy dz Jo Jo J -1

A: Here we have to solve the givne triple integral I=∫02∫01∫-14xyz3dxdydz

Q: Evaluate the iterated integral. [[ (x + y) dx dy

A:

Q: evaluate the iterated integral.

A:

Q: Evaluate the iterated integral. 4 (3x + y) dx dy 0. 4 (Зх + у) dx dy

A: Given: I=∫06∫04(3x+y)dxdy

Q: Evaluate the iterated integral. 5 2 y dy dx 10 Vx+y 5 2

A: Given, I=∫15∫02 yx+y2dy dx To Evaluate I.

Q: Evaluate the iterated integral 3 In z x e' dy dz dx

A: Given,         ∫13∫xx2∫0lnzxedydzdx

Q: Evaluate the iterated integral. V 4 - y2 (x + y) dx dy

A: