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Evaluate the integral: dx = S 3x²+14x+3 (x−1)(x+1)² +C

Evaluate the integral: dx = S 3x²+14x+3 (x−1)(x+1)² +C

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.CR: Chapter 6 Review
Problem 43CR
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Evaluate the integral : S 3x²+14x+3 (x-1)(x+1)²' dx = +C
Transcribed Image Text:Evaluate the integral : S 3x²+14x+3 (x-1)(x+1)²' dx = +C
Problem 9) Evaluate the Integral: 3 x ² + 14x + 3√x = A + 2 (X-1) (X+1) ² A (X-1)(X+1) ² + 0²-11 с B +C (X-1) (x+1) (x+1)² LCD= (x-1) (X+) ² 2 (x-1) (x + 1)² + C (x-1)(x+1) ² (x+1)= 1 B (x++) -10 Ө 2 ·A (x + 1)² + B (x-1) (x + 1) + C (x-1): X = 1; 4A = 3 + 14+3 = 4A = 20 = A=5 X=-1; -2C₂-8 = C=4 Y₂0 5+1 5 +1 + B (-1) (1) + 4 (-1) = 3 ! dus²²² +C 5-B - 4 1 1 2 3 -1 > B = -2 dvad -2+1 S²₁ ²504 + 45 x 4 1/² dx 2 (x-1) ((x+1) U₂8+1 du z dx 5/n/x-1/-2)x+1/= 4/n/x+1/+c ↓ ? U + C # -10t+C
Transcribed Image Text:Problem 9) Evaluate the Integral: 3 x ² + 14x + 3√x = A + 2 (X-1) (X+1) ² A (X-1)(X+1) ² + 0²-11 с B +C (X-1) (x+1) (x+1)² LCD= (x-1) (X+) ² 2 (x-1) (x + 1)² + C (x-1)(x+1) ² (x+1)= 1 B (x++) -10 Ө 2 ·A (x + 1)² + B (x-1) (x + 1) + C (x-1): X = 1; 4A = 3 + 14+3 = 4A = 20 = A=5 X=-1; -2C₂-8 = C=4 Y₂0 5+1 5 +1 + B (-1) (1) + 4 (-1) = 3 ! dus²²² +C 5-B - 4 1 1 2 3 -1 > B = -2 dvad -2+1 S²₁ ²504 + 45 x 4 1/² dx 2 (x-1) ((x+1) U₂8+1 du z dx 5/n/x-1/-2)x+1/= 4/n/x+1/+c ↓ ? U + C # -10t+C
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