Evaluate the integral by interpreting it in terms of areas. L² (3x-14) de Part 1 of 3 We are concerned with the segment of the line y=x-14 that begins at (0, -14) and that ends at (7, 21/2✔ Part 2 of 3 Part 3 of 3 y Therefore, 10 5 -51 -10 -15 2 2-14 dx s 4 x-140 <- 14 dx can be interpreted as the area of the triangle above the x-axis minus the area of the triangle below the x-axis. The area of the lower triangle is bh = 28✔ 175 4 6 X X 21/2). 28 and the area of the upper triangle is 63

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Tutorial Exercise
Evaluate the integral by interpreting it in terms of areas.
(1²-14) de
Part 1 of 3
We are concerned with the segment of the line y =
= 1/2/²
x-14 that begins at (0, -14) and that ends at (7, 21/2✔
Part 2 of 3
Part 3 of 3
Therefore,
y
10
- 10
-15
6² ²2² × -
2
x - 14 dx =
12/1
x - 14 dx can be interpreted as the area of the triangle above the x-axis minus the area of the triangle below the x-axis. The area of the lower triangle is
4
175
4
6
X
X
21/2).
bh =
28 and the area of the upper triangle is 63/4
63/4.
Transcribed Image Text:Tutorial Exercise Evaluate the integral by interpreting it in terms of areas. (1²-14) de Part 1 of 3 We are concerned with the segment of the line y = = 1/2/² x-14 that begins at (0, -14) and that ends at (7, 21/2✔ Part 2 of 3 Part 3 of 3 Therefore, y 10 - 10 -15 6² ²2² × - 2 x - 14 dx = 12/1 x - 14 dx can be interpreted as the area of the triangle above the x-axis minus the area of the triangle below the x-axis. The area of the lower triangle is 4 175 4 6 X X 21/2). bh = 28 and the area of the upper triangle is 63/4 63/4.
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