Evaluate the given function using homogeneous x- yArctan () dx + xArctan () dy = 0 A. 2yArctan () [c² (x² + y²)] = xln x4 y (y² + x²' B.xlnx? + 2yArctan-xln x2 = 2xlnC C. xlnx2 + 2yArctan- y y2 + x² xln 2lnC | x2 D.None of the Above

Q: ) Estimate the value of Csc (0. 2) using linear approximation and without using any kind of…

A: Given problem:- Estimate the value of csc(0.2) using linear approximation

Q: equilibrium

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Q: . Suppose that your best friend has calculated the partial derivatives of a given function f(x,y)…

A: Please see the below picture for detailed solution for detailed solution.

Q: If f(x, y, z) = 12ry - 2yz - 6zx + 7, then the first order partial derivative f = O - (2y – 6x) (2y…

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Q: Find the most general antiderivative of the function. 2xA + 7x³ - x F(x) + x >0 %3D F(x) %3D

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Q: The antiderivative of the function 4 .3 + 10x³ is, 4 f(x) - -4 .3 + 2.5x³ + c 4 -10 + 1.0xª + c -4 +…

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Q: x² + y² F(x, y) =- - is a homogeneous function of degree

A: For finding degree of homogeneous function, Put x=hx and y=hy

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Q: x² – y² = = CX

A: For orthogonal trajectories, replace dy/dx by -dx/dy and solve it.

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Q: hich vect וdtiolו y and 2? 1 -2 y = 1 -6 x = 2 8 -1 2 -1 5 2 -3 [ 2 -1

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Q: Solve: sec x = V2 + 2πkk e Z U + 2π시k E Z 3. + 2πkke z 2Tk k EZ 4. 4 + 2rk|k € Z 3 + 2rk|k E Z 3. of…

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Q: Show that the linearization of f(x) = (1 + x)k at x = 0 is L(x) = 1+ kx.

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Q: Consider a competitive market in which price adjusts to excess demand or supply and firms enter and…

A: given that                                                 dpdt=0.5qD-qs where qD is demand…

Q: Find and sketch the domain of the function. f(x, y, z) = ln(64 − 4x2 − 16y2 − z2)

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Q: Find and Sf Sf Sx dy f(x; y) = x 3 + 3x 2y - 9xy 3 = x2 + 3xy - 9y3; = 3x2 - 9xy² %3D 는- 3x2, 을…

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Q: Find ý of the function x2 - e2x+3y - In(xy) = 0. %3D

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Q: Find constants c1 and c2 such that F(x) = c1xe -x + c2e -x is an antiderivative of f(x) = 3xe -x .

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Q: 12. Differentiate the function (use chain rule): y = 2x2 Vx+1'

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Q: Integrate f(x) = 10 ( 1 – x)9 where 1 ≤ x ≤ 3, Using Boole’s rule

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