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Evaluate the definite integral by the limit definition. Step 1 J4 5 dx To find the definite integral 5 dx by the limit definition, divide the interval [4, 9] into n subintervals. Step 2 Then the width of each interval is b-a Ax = Note that ||A||- → n J4 5 n 9-4 n O as n→ 00.

Evaluate the definite integral by the limit definition. Step 1 J4 5 dx To find the definite integral 5 dx by the limit definition, divide the interval [4, 9] into n subintervals. Step 2 Then the width of each interval is b-a Ax = Note that ||A||- → n J4 5 n 9-4 n O as n→ 00.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.1: Inverse Functions
Problem 17E
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Evaluate the definite integral by the limit definition. [²5 Step 1 5 dx To find the definite integral Then the width of each interval is b-a Ax = Note that ||A|| → n = = Step 2 Choose c; as the right endpoint of each subinterval. Then C₁ = a + i(Ax) = So the definite integral is given by = = 5 = n [²5 dx = lim Σκ(c;) Δx IAI → 0 i = 1 = = n→ [² 5 dx by the limit definition, divide the interval [4, 9] into n subintervals. lim n→ ∞ n n→ lim Σ n→∞ i = 1 n→ lim n→∞0 O as n→→ ∞0. lim i = 1 lim lim n→ ∞ n 94 lim 25. +i A i = 1 1 f(c;) Ax + n (5) 1 n n i = 1 1)() 25
Transcribed Image Text:Evaluate the definite integral by the limit definition. [²5 Step 1 5 dx To find the definite integral Then the width of each interval is b-a Ax = Note that ||A|| → n = = Step 2 Choose c; as the right endpoint of each subinterval. Then C₁ = a + i(Ax) = So the definite integral is given by = = 5 = n [²5 dx = lim Σκ(c;) Δx IAI → 0 i = 1 = = n→ [² 5 dx by the limit definition, divide the interval [4, 9] into n subintervals. lim n→ ∞ n n→ lim Σ n→∞ i = 1 n→ lim n→∞0 O as n→→ ∞0. lim i = 1 lim lim n→ ∞ n 94 lim 25. +i A i = 1 1 f(c;) Ax + n (5) 1 n n i = 1 1)() 25
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