Evaluate both integrals of the Divergence Theorem for the following vector field and region. Check for agreement. F = (z-y,x,-x); D = {(x,y,z2); A. y² z² OB. -{-1} + 8 + 9 27 set up the surface integral for the Divergence meorem, using a parametrization with the form r= (a sin u cos v, b sin u sin v, c cos u) for the surface if needed. Select the correct choice below and fill in any answer boxes within your choice. 2x T JSO du dv, where the integrand does not simplify to a 00 constant The integral simplifies to to SS as dS. S (Type an integer or a simplified fraction.)

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter7: Locus And Concurrence
Section7.2: Concurrence Of Lines
Problem 7E: Which lines or line segments or rays must be drawn or constructed in a triangle to locate its a...
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Evaluate both integrals of the Divergence Theorem for the following vector
field and region. Check for agreement.
F = (z-y,x, - x);
set up the sanace negral or the Divergence meorem, using a
parametrization with the form r= (a sin u cos v, b sin u sin v, c cos u) for
the surface if needed. Select the correct choice below and fill in any
answer boxes within your choice.
A.
OB.
x² y² z²
D={(xyz) - 2 + 1 -1}
+
9 27 8
21 T
JSO du dv, where the integrand does not simplify to a
00
constant
SS
S
(Type an integer or a simplified fraction.)
The integral simplifies to
ds.
Transcribed Image Text:Evaluate both integrals of the Divergence Theorem for the following vector field and region. Check for agreement. F = (z-y,x, - x); set up the sanace negral or the Divergence meorem, using a parametrization with the form r= (a sin u cos v, b sin u sin v, c cos u) for the surface if needed. Select the correct choice below and fill in any answer boxes within your choice. A. OB. x² y² z² D={(xyz) - 2 + 1 -1} + 9 27 8 21 T JSO du dv, where the integrand does not simplify to a 00 constant SS S (Type an integer or a simplified fraction.) The integral simplifies to ds.
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