Ethyl lodide decomposes at high temperatures according to the reaction shownhere:C2H5I(g) --> C2H4(g) + HI(g)The concentration of ethyl iodide is followed over time and shown in the tablebelow-Time(min) [C2H51] (M)010.36150.30300.25450.19600.13Determine the order of the reaction and the rate constant. a.1st order, k=0.014 min1Ob.Ob. I get a different answer.C.2nd order, k-0.0042 M-1min1Od. oth order, k=120 M/min

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Ethyl lodide decomposes at high temperatures according to the reaction shown here: C2H5I(g) - C2H4(g) + HI(g) --> The concentration of ethyl iodide is followed over time and shown in the table below- Time(min) [C2H5I] (M) 0. 0.36 15 0.30 30 0.25 45 0.19 60 0.13 Determine the order of the reaction and the rate constant.

Ethyl lodide decomposes at high temperatures according to the reaction shown here: C2H5I(g) - C2H4(g) + HI(g) --> The concentration of ethyl iodide is followed over time and shown in the table below- Time(min) [C2H5I] (M) 0. 0.36 15 0.30 30 0.25 45 0.19 60 0.13 Determine the order of the reaction and the rate constant.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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