find the equation of the tangent line f(x)=cos x, f'(x)=sin x, x=2pi/3
I am getting y=sq rt 3/2x - 2pi/3 - 1/2. Is this correct?
Please refer to the image below
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what excatly are you doing between lines 3 and 4 that gets -2pi/3 (in line 3) changed to -pi/sq rt 3 (in line 4)?