equation: Pb(s) + PbO2(s) + 2H2SO4(aq) - 2PbS04(s) + 2H2O(1) Look up standard potentials for the oxidation and reduction half-reactions, and then calculate the value of Ecell E cell +2.041 Calculate the value of AGxn -393.9 AGrxn = Calculate the value of Ecell at 25 °C if [H2SO4] = 10.0 M.

Please explain, answer 0.57 V

8

Predict reaction and calculate E°cell from standard reduction potentials. A voltaic cell is constructed from a standard AI3+|Al half cell (E°red = -1.660V) and a standard F2|F° half cell (E°red = 2.870V). What is the spontaneous reaction that takes place, and what is the standard cell potential? Spontaneous cell reaction:Write a balanced equation using the smallest integer coefficients possible. + Standard cell potential: V.

Consider a voltaic cell in which the following reaction takes place. 2Fe 2+ (aq) + H₂O2 (aq) + 2 H+ (aq) --→2Fe ³+ (aq) +2H₂O (1) calculate Eº Calculate E and Gibbs free energy when [Fe²+] = 0.00813 M, [H₂O₂] = 0.914 M, [Fe ³+] = 0.199 M, [H] = 1.32 x 10³ M

A voltaic cell is constructed with two silver electrodes, where the half-reaction isAg2+(aq) + 2e- → Ag (s)   E° = -0.322 VDetermine the cell emf at 25 °C when the concentrations of chloride ion in the two compartments are 4.0 Mand 0.050 M, respectively.

A voltaic cell using Pb²⁺/Pb and Ni²⁺/Ni half-cells is set up at standard conditions, and each compartment has a volume of 355 mL. What is the cell potential, in V, after it has delivered 0.150 A for 51.0 hours at 25.0 °C? (E° for Pb²⁺/Pb = -0.130 V and E° for Ni²⁺/Ni = -0.250 V.)

In a Voltaic cell composed of CuôCu(NO3)2 and AgôAgNO3 half-cells, what is the spontaneous cell reaction and the Eocell, respectively? The standard reduction potentials are as follows:                    Ag+(aq)  +  e–  -->  Ag(s);       Eo = 0.80 V                  Cu2+(aq)  + 2e–  -->  Cu(s);      Eo = 0.34 V          (A) 2Ag(s) + Cu2+(aq)  -->  2Ag+(aq) +  Cu(s);    Eocell = 1.14 V          (B) 2Ag(s) + Cu2+(aq)  -->  2Ag+(aq) +  Cu(s);    Eocell = 1.94 V          (C) Cu(s) + 2Ag+(aq)  -->  Cu2+(aq)  +  2Ag(s);  Eocell = 0.46 V          (D) Cu(s) + 2Ag+(aq)  -->  Cu2+(aq)  +  2Ag(s);  Eocell = 1.26 V