
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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![Rate laws can be entered as strings in the answer box. For example, for aA(aq) + bB(aq) →
CC(aq) with the rate being second order in A and first order in B you enter k*[A]^2*[B] and
for aA(g) + bB(g) cC(g) with the rate being second order in A and first order in B using
pressures you enter k*P_{A}^2*P_{B}.
The reaction 2NO(g) + O2(g) → 2NO2(g) is second order in NO and first order in 02. Write the
rate law for the reaction in terms of pressures PNO and Po2 . Let us agree not to use
subscripts on subscripts. So, to enter the pressure of 02 use P_{02} and not P_{O_2}.
Units can be entered using mol/(L s) note the parenthesis and the space between L and s.
Enter the units of r when the pressure is measured in bar and time in min. (use the backslash
/ but be sure to use () when more than one
unit is is the denominator)
Units of r =
Enter the units of r when the amount is measured in mol L1 and time in min (use the
backslash / but be sure to use () when more than one
unit is is the denominator and a space or * to mean the product, for example: L/(mol s) or
L/(mol*s) or L/(s mol) or L/(s*mol) )
Units of r =
%3D
Enter the following rate law for the decomposition of 03:
2k1 k2[O3]°
k _1[O2] + k2[O3]
as a string
using the string 2*k_1*k_2*[O_3]^2/(k_{-1}*[O_2] + k_2*[O_3]) try typing it instead of using
copy and paste. Note that here we use O_3, but we do not use 0_{3} because the subscript is a
single character.](https://content.bartleby.com/qna-images/question/6201d558-9339-4c2b-9e00-e7ccdb6138bf/340f2e78-1c7e-45bf-b83e-817505d9122d/vzz5sz_thumbnail.jpeg)
Transcribed Image Text:Rate laws can be entered as strings in the answer box. For example, for aA(aq) + bB(aq) →
CC(aq) with the rate being second order in A and first order in B you enter k*[A]^2*[B] and
for aA(g) + bB(g) cC(g) with the rate being second order in A and first order in B using
pressures you enter k*P_{A}^2*P_{B}.
The reaction 2NO(g) + O2(g) → 2NO2(g) is second order in NO and first order in 02. Write the
rate law for the reaction in terms of pressures PNO and Po2 . Let us agree not to use
subscripts on subscripts. So, to enter the pressure of 02 use P_{02} and not P_{O_2}.
Units can be entered using mol/(L s) note the parenthesis and the space between L and s.
Enter the units of r when the pressure is measured in bar and time in min. (use the backslash
/ but be sure to use () when more than one
unit is is the denominator)
Units of r =
Enter the units of r when the amount is measured in mol L1 and time in min (use the
backslash / but be sure to use () when more than one
unit is is the denominator and a space or * to mean the product, for example: L/(mol s) or
L/(mol*s) or L/(s mol) or L/(s*mol) )
Units of r =
%3D
Enter the following rate law for the decomposition of 03:
2k1 k2[O3]°
k _1[O2] + k2[O3]
as a string
using the string 2*k_1*k_2*[O_3]^2/(k_{-1}*[O_2] + k_2*[O_3]) try typing it instead of using
copy and paste. Note that here we use O_3, but we do not use 0_{3} because the subscript is a
single character.
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Enter the units of r when the amount is measured in mol L-1 and time in min (use the backslash / but be sure to use () when more than one unit is is the denominator and a space or * to mean the product, for example: L/(mol s) or L/(mol*s) or L/(s mol) or L/(s*mol) )
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Enter the units of r when the amount is measured in mol L-1 and time in min (use the backslash / but be sure to use () when more than one unit is is the denominator and a space or * to mean the product, for example: L/(mol s) or L/(mol*s) or L/(s mol) or L/(s*mol) )
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- The gas phase decomposition of hydrogen peroxide at 400 °C H2O2(g)H20(g) + ½ O2(g) is second order in H2O2. In one experiment, when the initial concentration of H,O2 was 0.242 M, the concentration of H,O, dropped to 4.09×10 M after 23.5 seconds had passed. Based on these data, the rate constant for the reaction is M1s1.arrow_forwardIn a study of the gas phase decomposition of nitrogen dioxide at 383 °C NO₂(g) →→→NO(g) + ½ O₂(g) the concentration of NO₂ was followed as a function of time. It was found that a graph of 1/[NO₂] versus time in seconds gave a straight line with a slope of 0.815 M-¹ s¹ and a y-intercept of 11.5 M-¹. Based on this plot, the reaction is [ ✓order in NO₂ and the rate constant for the reaction is M-¹ S-¹.arrow_forwardThe recombination reaction 2 HO₂(g) → H₂O2(g) + O₂(g) has a second-order rate constant of 1.8E9 M1 s1. Calculate the half-life of the reaction if the initial concentration of HO₂(g) is 1.7E-11 M. Note: the coefficient 2 in the reaction means that the integrated rate law for this reaction is: 1/c = 1/co+2kt Include at least 3 significant figures in your answer. Show Transcribed Textarrow_forward
- - 1 Under certain conditions the rate of this reaction is zero order in hydrogen iodide with a rate constant of 0.0020 M·s 2 HI (g) → H, (g) + I, (g) Suppose a 4.0 L flask is charged under these conditions with 150. mmol of hydrogen iodide. How much is left 5.0 s later? You may assume no other reaction is important. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.arrow_forward5. You studied the chemical reaction, 2NO2(g) → 2NO(g) + O2(g), at 25°C by monitoring the concentration of NO2(g) as a function of time and constructed the following graph. y= 0.5408x + 125.0 R2=0.998 Time (s) What is the rate constant for this reaction at 25°C? Include the proper units. (W/T) [(3)ONI/Tarrow_forwardBe sure to answer all parts. The rate law for 2 NO(g) + O2(g)→ 2 NO2(g) is rate = k[NO]°[O2l. %3D The following mechanisms have been proposed: I. 2 NO(g) + O2(g)→ 2 NO2(g) II. 2 NO(g) = N½O2(g) [fast] N,O2(g) + O2(g) → 2 NO,(g) [slow] III. 2 NO(g) = N,(g) + O2(g) [fast] N2(g) + 2 O2(g) → 2 NO2(g) [slow] (a) Which of these mechanisms is consistent with the rate law? Check all that apply. I. II. III. None of the above (b) Which of these mechanisms is most reasonable? I. II. III.arrow_forward
- Questions 2A 2B and 2C pleasearrow_forwardGive answer to all partsarrow_forwardA value of k is found from the rate equation Rate = k[A]m[B]n. If m=1 and n=4 and -1 the unit for the initial rate is M/h. The unit of k is found to be MX h-¹ (M to the power of x h to the power of minus 1). What is the value of x?arrow_forward
- The rate at which a certain drug is eliminated by the body follows first-order kinetics, with a half life of 73 minutes. Suppose in a particular patient the concentration of this drug in the bloodstream immediately after injection is 1.1 ug/mL. What will the concentration be 365 minutes later? Round your answer to 2 significant digits. ug x10 mL ?arrow_forward6. To observe the effect of temperature on reaction rate, the reaction between MnO, ag) and C204(ag) in acidic media is performed according to the given redox reaction: 2 MnO4 (aq) + 16 H*(aq) + 5 C204²(aq) → 10 CO2(g) + 2 Mn²"(aq) + 8 H2O(1) At various temperatures, the rate constants were determined experimentally as follows: k (M s') 5.03x105 T (°C) 20 35 3.68×104 60 6.71×103 90 0.119 (a) Determine Ea for this reaction by a graphical method (see the graph given below). (b) Determine E. using Arrhenius equation using tabulated data. (c) Calculate the value of the rate constant, k at 100°C. -2 -4 兰 -6 -8 -10 -12 0.0025 0.0027 0.0029 0.0031 0.0033 0,0035 1/T (K)arrow_forward
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