MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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Engineers want to design seats in commercial aircraft so that they are wide enough to fit95% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are
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- Engineers want to design seats in commercial aircraft so that they are wide enough to fit 90% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.3 in. and a standard deviation of 0.9 in. Find P That is, find 90 the hip breadth for men that separates the smallest 90% from the largest 10%. DOL The hip breadth for men that separates the smallest 90% from the largest 10% is P (Round to one decimal place as needed.) 90 in.arrow_forwardEngineers want to design seats in commercial aircraft so that they are wide enough to fit 95% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.5 in. and a standard deviation of 1.1 in. Find P95. That is, find the hip breadth for men that separates the smallest 95% from the largest 5%arrow_forwardEngineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.6 in. and a standard deviation of 0.8 in. Find P99. That is, find the hip breadth for men that separates the smallest 99% from the largest 1%. Question content area bottom Part 1 The hip breadth for men that separates the smallest 99% from the largest 1% is P99=enter your response here in.arrow_forward
- Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.1 in. and a standard deviation of 0.8 in. Find P99. That is, find the hip breadth for men that separates the smallest 99% from the largest 1%. What'sThe hip breadth for men that separates the smallest 99% from the largest 1% is P99=nothing in.arrow_forwardEngineers want to design seats in commercial aircraft so that they are wide enough to fit 90% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.1 in. and a standard deviation of 0.8 in. Find P90. That is, find the hip breadth for men that separates the smallest 90% from the largest 10%. The hip breadth for men that separates the smallest 90% from the largest 10% is P90=[ ] in.arrow_forwardEngineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all adults. (Accommodating 100% of adults would require very wide seats that would be much too expensive.) Assume adults have hip widths that are normally distributed with a mean of 13.6 in. and a standard deviation of 1.2 in. Find P99. That is, find the hip width for adults that separates the smallest 99% from the largest 1%. What is the maximum hip width that is required to satisfy the requirement of fitting 99% of adults? in. (Round to one decimal place as needed.)arrow_forward
- Engineers want to design seats in commercial aircraft so that they are wide enough to fit 90%of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.7in. and a standard deviation of 1.2in. Find P90. That is, find the hip breadth for men that separates the smallest 90% from the largest 10%. The hip breadth for men that separates the smallest 90%from the largest 10% is P90=nothing in. (Round to one decimal place as needed.)arrow_forwardEngineers want to design seats in commercial aircraft so that they are wide enough to fit 95% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.3 in. and a standard deviation of 0.9 in. Find Pas. That is, find the hip breadth for men that separates the smallest 95% from the largest 5%. The hip breadth for men that separates the smallest 95% from the largest 5% is Pas = in. (Round to one decimal place as needed.)arrow_forwardEngineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.8 in. and a standard deviaof 1.1 in. Find Pog. That is, find the hip breadth for men that separates the smallest 99% from the largest 196. The hip breadth for men that separates the smallest 99% from the largest 1% is Peg-. in. (Round to one decimal place as needed.)arrow_forward
- Engineers want to design seats in commercial aircraft so that they are wide enough to fit 90% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.2in. and a standard deviation of1.1in. FindP90. That is, find the hip breadth for men that separates the smallest 90% from the largest 10%.arrow_forwardEngineers want to design seats in commercial aircraft so that they are wide enough to fit 95% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.5 in. and a standard deviation of 0.8 in. Find P95. That is, find the hip breadth for men that separates the smallest 95% from the largest 5%.arrow_forwardEngineers want to design seats in commercial aircraft so that they are wide enough to fit 95% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.3 in. and a standard deviation of 1.1 in. Find P95. That is, find the hip breadth for men that separates the smallest 95% from the largest 5%.arrow_forward
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