Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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encrypt the message NEED HELP by translating the letters into numbers, applying the encryption function f(p)=(p+3) mod 26, and then translating the numbers back into letters
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- Help with this pleasearrow_forwardAlice wishes to tell Bob about the animal she saw at the zoo Alice and Bob share the key stream 1101 1001 0000 1010 1110 1101 Alice creates a 3-character ASCII message, encodes it, and sends it to Bob. This is the ciphertext: 1001 1111 0100 0101 1011 0101 Bob deciphers the message. What animal did Alice see at the zoo?arrow_forwardIn XOR Cipher, encoding is done by an XOR operation on two given strings. If the strings are of different lengths then the output should be the length of the shorter string. Cut the length of the longer string to the same size as the smaller string before XOR operation. Given two strings of msg1 and msg2, return the encoded message. Examples xor_cipher ("11", "22") "33" # 11 XOR 22 = 33 RUBY xor_cipher ("1020304", "403201") xor_cipher ("c611d9bdd9de38b9eb", "23a0745505d4d25494") "e5b1ade8dc0aeaed7f" "501231"arrow_forward
- In the case of Public Key Authority It is necessary to make a request for B's public key, and the Public Key Authority must prepare a message (E(PRauth[PUB] || Request || Time1]) before sending it to A. What key A should use to decipher the message is up for debate.arrow_forwardThe following figure is the Cipher Block Chaining (CBC) mode to encrypt large messages. Which of the followings statement is *correct* regarding this mode? IV m₁ m₂ m3 C3 m4 C4 m5 C5 If a message contains two identical 64-bit blocks, the corresponding ciphertext blocks are also identical. Switching the order of two cipher blocks will not cause any detectable error in the plaintext. Duplicating a cipher block will not cause any detectable error in the plaintext. Deleting a cipher block will cause some detectable error in the plaintext. m6 E encrypt with secret key C6arrow_forwardSuppose you intercepted the following encrypted message: 20 5 21 3 49 4 49 3 4 15 You also know the encryption key is d=7 and it was determined using n=55. Decrypt this message. Assume that letters 'A' through 'Z' were initially coded using 1 through 26 and a blank was initially coded using 27. no hand wriitenarrow_forward
- Urgent! Answer the question belowarrow_forwardUse symmetric ciphers to encrypt message "“promise" and decrypt message "FOG". The representation of characters in modulo 26 is described as follows: Plaintext - a bcdefg|hijk1 mnopar stuvwx y z Ciphertext A BCD|EFG|HIJKL|M|NO|P|Q|R s T|U|VwxY|Z Value 00 01 02|03 04 05 06|07|08|09|10|11 12|13|14|15 16|17 18|19 20 21 22 23 24 25 The mathematical equations for encryption and decryption can be described as follows: Encryption Ea:i→i+kmod 26 Decryption Da : i→i-k mod 26 i represents the messages (plaintext or cipher), k represents a symmetric key. In this case k=20arrow_forwardPlz don't use chat gptarrow_forward
- 21. RSA problem: given plaintext P, e, prime numbers p, q, compute ciphertext C. Decrypt C and verify you get plaintext P back.arrow_forwardOne of the one-way functions used in public key cryptography is integer multiplication/factorization. Multiplying two integers is easy, but factoring is hard. The number 1765243 is the product of two primes. What is the smaller of the two primes? What is the largest of the two primes?arrow_forwardAlice sets up an RSA public/private key, but instead of using two primes, she chooses three primes p, q, and r and she uses n=pqr as her RSA-style modulus. She chooses an encryption exponent e and calculates a decryption exponent d. Encryption and Decryption are defined: C ≡ me mod n and m ≡ Cd mod n where C is the ciphertext corresponding to the message m. Decryption: de ≡ 1 mod φ(n) | Let p = 5, q = 7, r = 3, e = 11, and the decryption exponent d = -13. n = 105 & φ(n) = 48 Q: Alice upgrades to three primes that are each 200 digits long. How many digits does n have?arrow_forward
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