Element R has a molecular weight of 72.00 Element A has a molecular weight of 22.00 Given the reaction  2R + 3A  =   R2A3 If we start with 230 grams of R and 100 grams of A (READ CAREFULLY it is 230 g R and 100 g A!!!) How many moles of R2A3 can we theoretically make? What is the limiting reactant? If we actually make 0.40 moles of R2A3 what was our yield?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Given for this problem:

Element R has a molecular weight of 72.00   Note!! Element R is not a real element.

Element A has a molecular weight of 22.00   Note!! Element A is not a real element.

Given the reaction  2R + 3A  =   R2A3

q = mass X specific heat X (Tfinal - Tinitial)

specific heat of water is 4.184 J/g oC

% Yield = (actual/theoretical) X 100

Given this hypothetical activity series:

Li > Na > Mg > A > Al > Zn > H > Cu > R > Ag > Pt

Element R has a molecular weight of 72.00

Element A has a molecular weight of 22.00

Given the reaction  2R + 3A  =   R2A3

If we start with 230 grams of R and 100 grams of A (READ CAREFULLY it is 230 g R and 100 g A!!!)

How many moles of R2A3 can we theoretically make? What is the limiting reactant? If we actually make 0.40 moles of R2A3 what was our yield?

 

 

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