%3D In the balanced three-phase delta-wye system shown below, V = 44020° V rms, V = 440Z-120° V rms, V = 440Z-240° v rms, Z = 0.5+ jl.5 Q, %3D са bc Z, = 4.5+ j10.5 2, find the (a) magnitude of line current and the average power delivered %3D to the load. ZF la a Zy Zy ZY ZE C B ZF
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- The one-line diagram of a three-phase power system is shown in the above figure. The line impedances are in per- unit on a 100-MVA base, and the line admittances are neglected. Use Gauss-Seidel method in Matlab to analyze the system the tolerance of error is 10-3. Then anwser the questions as follows. V, = 1.05200 0.01+ j0.025 300 + j200 MVA 0.015 + j0.035 150 MW 200 +j150 MVA 0.01+ j0.03 |V = 1.03 The admittance matrix (Y_bus)? 0.02 + jo.04 0.0125 + jo.03 2.Two balanced loads are connected to the a 240kVrms60Hz line as shown in the figure below. Load 1 draws30kW at a power factor of 0.6 lagging and load 2 draws 45 kVAR at power factor of 0.8 lagging. The real power, reactive power, and magnitude of the line current absorbed by the combined load is close to kW, kVAR, and A. Two balanced loads are connected to the a 240kVrms 60Hz line as shown in the figure below. Load 1 draws 30kW at a power factor of 0.6 lagging kW. and load 2 draws 45KVAR at power factor of 0.8 lagging. The real power absorbed by the combined load is close to Balanced load 1 Balanced load 2AC Power and Power Factor 1. Two loads are connected in parallel across a 13,200-volt line. Load A draws 200kW at 0.6 p.f. (lagging), load B takes 200kVA at 0.8 p.f. (lagging). Find the reactive, apparent and true power and the line current.
- The one-line diagram of a three-phase power system is shown in the above figure. The line impedances are in per- unit on a 100-MVA base, and the line admittances are neglected. ' qu V = 1.05200 0.01+ j0.025 300 + j200 MVA 3 0.015 + j0.035 150 MW 200 + j150 MVA 0.01 + j0.03 |V = 1.03 The admittance matrix (Y_bus)? The bus power in per-unit?A balanced Y-connected generator with terminal voltage Vbc 5 200/08 volts is connected to a balanced-D load whose impedance is 10/408 ohms per phase. The line impedance between the source and load is 0.5/808 ohm for each phase. The generator neutral is grounded through an impedance of j5 ohms. The generator sequence impedances are given by Zg0 5 j7, Zg1 5 j15, and Zg2 5 j10 ohms. Draw the sequence networks for this system and determine the sequence components of the line currents.Draw a 3-phase wye-connected generator with transmission lines connected to a 3-phase delta-connected load. Assume the lines connecting them have an inductance of j5 per phase. The generated voltages are 120 Vrms with phase 'a' having a phase angle of 0°. The loads are 10 Ohm resistors per phase. When drawing, make sure to label all 3 phases with voltage phasors, line inductances, and load resistances.
- an a transmission line has an impedance of 4 j2 Ohms/phase, Find the per-unit impedance of this line on a base of 100 MVA and 20 KV. Select one: O a. None of these Ob. 20-j10 (p.u) Oc 1-0.5 (p.u) O d. 0.5-j1 (p.u)In a balanced Y-Y circuit shown in Figure 5, the magnitude of the phase voltage at the source is Vp = 2520 V (rms) and Van = 252020° V (rms). The load impedance is Zy = 135 + j55 Q per phase and the wire impedance is Zw=85 + j65 per phase. All the voltages and currents are in rms in this problem. (a) Find the phasors for line currents IA, IB, Ic in rms. (b) Find the load voltage VAN = IAZY. Also find VBN, and VCN. (c) Find the line voltages VAB, VBC, VCA at the load. (d) Find the complex power SL of the load. ZW ZY Van a A IA ZW ZY Vbn b В IB N ZW ZY Vcn IC Figure 5The one-line diagram of a three-phase power system is shown in the above figure. The line impedances are in per- unit on a 100-MVA base, and the line admittances are neglected. ' V, = 1.05200 0.01 + jo.025 300 +j200 MVA 3 0.015+j0.035 150 MW 200 +j150 MVA 4 0.01 + j0.03 |V2 = 1.03 The admittance matrix (Y_bus)? 0.02 + jo.04 0.0125 + jo.03
- 1. Given the circuit below, the phase voltages are given by Van = 20040° Vrms. The source impedance is 5 + j7 per phase and the wire impedance is 8 +j10 per phase. Let the load impedance be Zy = 50 ohms. Find: Van Vin Ven a. II, and Ic b. c. VAN, VBN, and VCN, and VAB, VBC, and VCA Z₂ Z₂ Z₂ Zw Zw Zw B C le NVA-120 V4120 Z₁ volt In lc c ZA Three-phase source Feeder lines Balanced load In the above circuit diagram, we have source impedance Zg = 0.05+j0.15 ohm, Z₁ = 0.1+j0.2 ohm and per phase impedance in the balanced Delta connected load, Z₁ = 12+j9 ohm. RMS value of source voltage is 200 volt. Phase sequence is as shown in the diagram. RMS value of current Ic= ampere Phase angle of le= degree RMS value of line voltage VCA = B JAB Inc ICAGiven: 1. 2 wye-connected loads per phase to a 3 phase power source 2. first load consists of a 55ohm resistance and a 0.05H inductance per phase 3. second load consumes 1kW and power factor of 0.7 lagging per phase 4. RMS of voltage across the loads are 220V, frequency 120Hz per phase 5. single phase equivalent is shown in the figure: Question: Give the value of reactive power per phase seen at load 2.