-10 + 2 (5x10?) dU) + (6. 145) du) dt? + VCE) = 10 b) at t=o う 8ledy state leached. switch is opened. 502 ree 2H ナ 50 VE SMF i()= ilo*)= 0A- v6)= vlot) =ov %3D ! The voltage acros capacitor won't change instantly. The current thoough inductor woni't change instanty,) 2) Given, t= 0 X com 201 50 VIE) Step2 b) a) at t>o 50n 20V L= 2H ナ kv in LOOPO - 20 + 50 i (t) + 2 dilf)+ v (t)=0 >0 KCL in toope -i (E) + V (E) + i, O = o 50 - i () + v(H) +(5x103) dVIE)_ 50 difterentiafe it. dt 50 dt 20+50 - 10+ 25 50 50 JE

Consider a circuit with three capacitors connected in series. The capacitances are C₁ = 2.3 μF, C₂ = 1.8 μF, and C3 = 5.1 µF. What is the equivalent capacitance (in µF) of the three capacitors? 0.811 X x Are the capacitors connected in series or parallel? Remember that for capacitors in series, 0.677 C₁ = 2.3 μF 1 C3 = 5.1 μF eq = If a 17.0 V potential is applied to the circuit, what is the charge (in µC) of each capacitor? 14.33 ✓ Correct. We know the equivalent capacitance from the previous question. We also know that the charges on capacitors connected in series are the same. Thus, we can multiple the equivalent capacitance by the applied potential to determine the charge. µC If we now connect C₁ in series to C₂ and C3 in parallel, what is the equivalent capacitance (in µF)? (Note: C₁ = 2.3 µF, C₂ = 1.8 µF, and C3 = 5.1 µF.) C₂ = 1.8 μF 1 Ceq 1 ¡C; while in parallel: Ceq = = ΣC, UF X x Are the capacitors connected in series or parallel? Remember that for capacitors in series, -¹…

The current in a 24-mH inductor is given by the waveform in the figure below. Find the waveform for the voltage across the inductor.

RC circuit after the capacitor is charged, the switch is moved to dischsrge. The capacitor discharges through the resistance and voltage across the capacitor. Find time (t) if V=60V, R=1.0kΩ, & C=5µF. a. Vc=15V b. Vc=5.0V