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Edwin conducted a survey to find the percentage of people in an area who smoked regularly. He defined the label "smoking regularly" for males smoking 30 or more cigarettes in a day and for females smoking 20 or more. Out of 635 persons who took part in the survey, 71 are labeled as people who smoke regularly. What is the 90% confidence interval for this population proportion? Answer choices are rounded to the hundredths place. O O 0.09 to 0.13 0.09 to 0.80 0.11 to 0.80 0.11 to 0.13

Edwin conducted a survey to find the percentage of people in an area who smoked regularly. He defined the label "smoking regularly" for males smoking 30 or more cigarettes in a day and for females smoking 20 or more. Out of 635 persons who took part in the survey, 71 are labeled as people who smoke regularly. What is the 90% confidence interval for this population proportion? Answer choices are rounded to the hundredths place. O O 0.09 to 0.13 0.09 to 0.80 0.11 to 0.80 0.11 to 0.13

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Edwin conducted a survey to find the percentage of people in an area who smoked regularly. He defined the label "smoking regularly" for males smoking 30 or more cigarettes in a day and for females smoking 20 or more. Out of 635 persons who took part in the survey, 71 are labeled as people who smoke regularly. What is the 90% confidence interval for this population proportion? Answer choices are rounded to the hundredths place. O O 0.09 to 0.13 0.09 to 0.80 0.11 to 0.80 0.11 to 0.13
Transcribed Image Text:Edwin conducted a survey to find the percentage of people in an area who smoked regularly. He defined the label "smoking regularly" for males smoking 30 or more cigarettes in a day and for females smoking 20 or more. Out of 635 persons who took part in the survey, 71 are labeled as people who smoke regularly. What is the 90% confidence interval for this population proportion? Answer choices are rounded to the hundredths place. O O 0.09 to 0.13 0.09 to 0.80 0.11 to 0.80 0.11 to 0.13
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