Educational Television In a random sample of 190 people, 144  said that they watched educational television. Find the  95%  confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.     ?

Q: People were polled on how many books they read the previous year. How many subjects are needed to…

A:

Q: Use the formula in this example to determine the sample size, n. The estimated prevalence is 16%,…

A: Given that  p=16%=0.16 , Margin of error=E=5%=0.05 91% confidence level

Q: Global Warming In April of 2014, a Gallup Poll of 1048 U.S. adults found that 25% of the respondents…

A: From the provided information, Sample size (n) = 1048 25% of the respondents were skeptical that…

Q: Use the confidence interval to find the margin of error and the sample mean. (0.142,0.300) The…

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Q: this theory. Round answers to 4 decimal places where possible. a. With 90% confidence the proportion…

A: It is given that Favourable cases, x = 56Sample size, n = 745Confidence level = 90%

Q: Use the confidence interval to find the margin of error and the sample mean. (0.276,0.440) The…

A: Given information- We have given the interval = (0.276, 0.440) We know that- Confidence interval =…

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: Educational Television In a random sample of  200  people,  140  said that they watched educational…

A: Given data, n=200 x=140 sample proportion p=xnp=140200p=0.7z-value at 99% confidence is Zc=2.576

Q: Express the confidence interval (78.7 % , 96.3 % ) in the form of p+ ME. %士 Question Help: Video…

A: Given,confidence interval(CI)=(78.7% , 96.3%)

Q: Given the significance level ?=0.02α=0.02 find the following: (a)    left-tailed critical ?∗z∗…

A: The level of significance, α=0.02 a) Left tailed critical value from normal table is -2.0537.…

Q: Use the confidence interval to find the margin of error and the sample mean. (0.392,0.490) The…

A: Given that, The confidence interval is 0.392, 0.490

Q: se the confidence interval to find the margin of error and the sample mean. (0.458,0.600) he margin…

A: The given confidence interval is (0.458,0.600)

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Given, Total size n = 140 No of ppl smoke x = 35 proportion p = xn = 35140 = 0.25 99% confidence…

Q: d their candidate. State your answers as percents rounded to 1 decim

A: Here it is given that -  Of the 619 randomly selected likely voters surveyed, 305 supported their…

Q: Use the sample data and confidence level given below to complete parts  (b)   A research institute…

A: Margin of error can be calculated as shown below.

Q: Educational Television In a random sample of 205 people, 143 said that they watched educational…

A:

Q: Use the confidence interval to find the margin of error and the sample mean. (0.328,0.430) The…

A: Given data,Lower limit=0.328Upper limit=0.430

Q: Educational Television In a random sample of 190 people, 150 said that they watched educational…

A: Solution: Let X be the number of people said that they watched educational television and n be the…

Q: Express the confidence interval (68.8 %, 79 %) in the form of p + ME. % ± 96 Question Help: Video…

A: Given CI=(68.8%,79%)

Q: A psychologist is interested in constructing a 99% confidence interval for the proportion of people…

A: From the provided information,Confidence level = 99%

Q: A magazine provided results from a poll of 1500 adults who were asked to identify their favorite…

A: A magazine provided results from a poll of 1500 adults who were asked to identify their favorite…

Q: A psychologist is interested in constructing a 99% confidence interval for the proportion of people…

A: The formula for the confidence interval for the proportion is,

Q: Educational Television In a random sample of 210 people, 154 said that they watched educational…

A: Number of people (n) = 210 Number of people who said that they watched educational television (x) =…

Q: Educational Television In a random sample of 190 people, 145 said that they watched educational…

A: The answer is given below:

Q: Construct a confidence interval for p, - p, at the given level of confidence. X, = 377, n, = 533, x,…

A:

Q: A magazine provided results from a poll of 2000 adults who were asked to identify their favorite…

A: It is given that among the 2000 respondents, 14% chose chocolate pie, and the margin of error was…

Q: According to a survey of 100 men and 900 women, 21% of men and 28% of women read for fun almost…

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Q: Determine the t score used for each confidence interval. A. n= 6 and 95% confidence B. n = 14 and…

A: (A) Obtain the t-score of the 95% confidence interval for n=6. The t-score of the 95% confidence…

Q: Express the confidence interval (79.7%, 93.5 %) in the form of p + ME. % ± %

A: The confidence interval is (79.7% , 93.5%)Lower confidence limit=79.7%Upper confidence limit=93.5%

Q: Out of 600 people sampled, 534 had kids. Based on this, construct a 95% confidence interval for the…

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Q: on In a random sample of 205 people, 142 said that they watched educational television. Find the 99%…

A: given data, n=205x=142p^=xn=142205=0.6927CI=0.99α=1-0.99=0.01Zc:=Zα/2=Z0.01/2= Z0.0050=2.576 [from…

Q: Educational Television In a random sample of 200 people, 155 said that they watched educational…

A:

Q: Find the 90% confidence interval of the true proportion of people who watched educational…

A:

Q: A psychologist is interested in constructing a 99% confidence interval for the proportion of people…

A: From the provided information,Confidence level = 99%

Q: survey of 2269 ​adults, 701 say they believe in UFOs.   Construct a 95% confidence interval for the…

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Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1241 males surveyed,…

A: We have given that,  X1 = 182, n1 = 1241  And  X2 = 139, n2 = 1047 Then,  We will find the 99%…

Q: se the formula in this example to determine the sample size, n. The estimated prevalence is 19%,…

A: Given that,

Q: Educational Television In a random sample of 210 people, 150 said that they watched educational…

A: Using Excel formula “=NORM.S.INV(1-(0.05/2))”, the critical value for 95% confidence interval is…

Q: Educational Television In a random sample of 195 people, 160 said that they watched educational…

A:

Q: In a recent poll, 150 people were asked if they liked olives, and 23% said they did. Find the margin…

A: Given: n=150 p=0.23 α=0.1

Q: Home Internet Access According to a study, 77% of adults ages 18-29 years had broadband Internet…

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.