edback e average angular displacement is given by the slope of the secant. We calculate f(0.2) and f(1.8) and use these values d the average rate of change between 0.2 to 1.8 seconds: Thus, avg angular displacement = msecant f(0.2) 120e = f(1.8) 120e ≈44.280879 = (0.2-12)2 0.3 +40 1.80.2 (1.8-1.2)2 0.3 +40 ≈ 76.143305 f(t₁) -f(to) t₁- to 76.143305 44.280879 ≈19.914016 We note that the slope is positive, therefore, on average, between 0.2 and 1.8 seconds, the angular displacement is increasing at a rate of 19.914016 degrees/second. Save Quit & Save Back Next

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 94E
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How is the answer 44 and 76? Please show all work

edback
and the average rate of change between 0.2 to 1.8 seconds:
e average angular displacement is given by the slope of the secant. We calculate f(0.2) and f(1.8) and use these values
Thus,
avg angular displacement
की
4
DEC
0 12 8
R
F
>
Q Search or enter website name
1/
%
5
= msecant
T
G
≈19.914016
We note that the slope is positive, therefore, on average, between 0.2 and 1.8 seconds, the angular displacement is increasing at
a rate of 19.914016 degrees/second.
6
m
B
f(0.2) = 120e
Y
f(1.8) = 120e
-
H
MacBook Pro
≈ 44.280879
f(t₁) - f(to)
t₁ - to
76.143305- 44.280879
&
7
1.8 0.2
Ⓒ
≈76.143305
-
(0.2-1.2)²
0.3
U
(1.8-1.2)2
* 00
0.3 +40
J
+40
tv Sall
1
N M
4
Save Quit & Save
(
9
K
0
A G
0
L
Back Next
-
P
W
A
+ 11
{
[
Transcribed Image Text:edback and the average rate of change between 0.2 to 1.8 seconds: e average angular displacement is given by the slope of the secant. We calculate f(0.2) and f(1.8) and use these values Thus, avg angular displacement की 4 DEC 0 12 8 R F > Q Search or enter website name 1/ % 5 = msecant T G ≈19.914016 We note that the slope is positive, therefore, on average, between 0.2 and 1.8 seconds, the angular displacement is increasing at a rate of 19.914016 degrees/second. 6 m B f(0.2) = 120e Y f(1.8) = 120e - H MacBook Pro ≈ 44.280879 f(t₁) - f(to) t₁ - to 76.143305- 44.280879 & 7 1.8 0.2 Ⓒ ≈76.143305 - (0.2-1.2)² 0.3 U (1.8-1.2)2 * 00 0.3 +40 J +40 tv Sall 1 N M 4 Save Quit & Save ( 9 K 0 A G 0 L Back Next - P W A + 11 { [
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