College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- A 5.0 kg ball is rolling north at 2.50 m/s when it collides with a 6.0 kg ball which isinitially at rest. Given that the collision is perfectly inelastic, calculate the final velocitiesof both balls.arrow_forwardA 2.00-g particle moving at 5.40 m/s makes a perfectly elastic head-on collision with a resting 1.00-g object. (Assume the 2.00-g particle is moving in the positive direction before the collision. Indicate the direction with the sign of your answer.) (a) Find the velocity of each particle after the collision. 2.00-g particle 1.00-g particle m/s m/s (b) Find the velocity of each particle after the collision if the stationary particle has a mass of 10.0 g. 2.00-g particle 10.0-g particle m/s m/s (c) Find the final kinetic energy of the incident 2.00-g particle in the situations described in parts (a) and (b). KE in part (a) KE in part (b) J J In which case does the incident particle lose more kinetic energy? case (a) case (b)arrow_forwardA bumper cap "A" (mass of A = 140kg) with a velocity of 15 km/hr hits a another car "B" (mass of B = 160kg) which was immobile before impact. The collision is perfectly elastic & the frictions are considered negligible. Calculate the time at which the bumper cars are 2m apart from each other after the collisionarrow_forward
- Consider the two pucks shown in the figure. As they move towards each other, the momentum of each puck is equal in magnitude and opposite in direction. Given that v; oreen = 12.0 m/s, and mblue is 25.0% greater than mareen, what are the final speeds of each puck (in m/s), if - the kinetic energy of the system is converted to internal energy? 30.0 30.0 Vgreen m/s V blue m/sarrow_forwardIn inelastic collision: a) Both linear momentum and energy are conserved. b) Linear momentum is conserved, but energy is not conserved. c) Linear momentum is not conserved, but energy is conserved. d) Both linear momentum and energy are not conserved.arrow_forwardAn object (A) of mass 28kg is moving in a direction that makes angle of 42 degrees north of east with a speed of 5.00m/s, while object (B) of mass 16kg is moving due north with a speed of 8m/s. The two objects idea and stick together in a completely inelastic collision. Find the magnitude of the final velocity of the two objects system after the collisionarrow_forward
- A truck with a mass of 2020 kg and moving with a speed of 17.0 m/s rear-ends a 832 kg car stopped at an intersection. The collision is approximately elastic since the car is in neutral, the brakes are off, the metal bumpers line up well and do not get damaged. (a) Calculate the initial momentum of the truck (in kg m/s). kg m/s (b) Calculate the final velocities (in m/s) for the truck and the car. vtf= m/svcf= m/s (c) Calculate the total momentum (in kg m/s) of the truck AND the car after the collision. kg m/s (d) Did you expect the results that you got for Part (a) and (c)? Yes, since momentum is conserved in a collision with no external forces acting on the colliding objects.No, since there were no forces acting on either the car or the truck during the collision. No, since kinetic energy may not be conserved.Yes, since the collision is inelastic.arrow_forwardTwo billiard balls collide in an elastic collision. Which statement about total energy and momentumof the two balls is true?a) both the energy and momentum of the system are conservedb) neither the energy nor momentum of the system are conservedc) the energy of the system is conserved, but the momentum is notd) the momentum of the system is conserved, but the energy is notarrow_forwardA truck with a mass of 1570 kg and moving with a speed of 17.5 m/s rear-ends a 652 kg car stopped at an intersection. The collision is approximately elastic since the car is in neutral, the brakes are off, the metal bumpers line up well and do not get damaged. (a) Calculate the initial momentum of the truck (in kg m/s). kg m/s (b) Calculate the final velocities (in m/s) for the truck and the car. Vf = m/s Vf = m/s (c) Calculate the total momentum (in kg m/s) of the truck AND the car after the collision. kg m/s (d) Did you expect the results that you got for Part (a) and (c)? O No, since kinetic energy may not be conserved. O Yes, since the collision is inelastic. O No, since there were no forces acting on either the car or the truck during the collision. O Yes, since momentum is conserved in a collision with no external forces acting on the colliding objects.arrow_forward
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